<h3>The time in fourth race is 43.04 seconds</h3>
<em><u>Solution:</u></em>
Given that,
Shelly is trying to improve her running time for a track race
She ran the first race in 43.13 seconds
Her time was 43.1 seconds in the second race and 43.07 seconds in the third race
<em><u>Therefore, pattern is:</u></em>
43.13, 43.1, 43.07 , ..
<em><u>Find the difference between each terms</u></em>
d = 43.13 - 43.1 = 0.03
d = 43.1 - 43.07 = 0.03
Thus the difference is same
<em><u>If this pattern continues what will shellys time be in the fourth race?</u></em>
Fourth race = third race - 0.03
Fourth race = 43.07 - 0.03 = 43.04
Thus the time in fourth race is 43.04 seconds
The answer would be down 2 units from the y intercept and right 1
Answer:
First, make the double negative a positive.
So, (-6/13) + (7/15)
Then multiply the numerator, 6×7=42
And denominator 13×15=195
42/195 simplify by dividing both by 3 so 14/65
1 box =1 foot so you would have to count the boxes away from her
20,825 because I think you just multiply 245 and 85 and that should be the answer