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wlad13 [49]
4 years ago
15

I need help on this question

Mathematics
1 answer:
rosijanka [135]4 years ago
3 0
I believe it is D. im not sure
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 How many​ flowers, spaced every 3 ​in., are needed to surround a circular garden with a 150​-ft ​radius? Use 3.14 for pi.
BARSIC [14]

Answer:

3,768\ flowers

Step-by-step explanation:

step 1

Find the circumference of the circular garden

The circumference of the circle is equal to

C=2\pi r

we have

r=150\ ft

\pi=3.14

substitute the values

C=2(3.14)(150)=942\ ft

step 2

<em>Convert feet to inches</em>

Remember that

1\ ft=12\ in

942\ ft=942*12=11,304\ in

step 3

Divide the circumference by 3 in to calculate the number of flowers

11,304/3=3,768\ flowers

5 0
3 years ago
Given that A = (9,9,2), B = (1,3,5) and C = (5,6,4), find the vector equation of the line through A and B.
weqwewe [10]

Answer:

It's not C

Step-by-step explanation:

Sorry bud I tried to help you out but i guessed wrong on my test, atleast its not C though:)

3 0
3 years ago
Please help me answer ASAP!
Schach [20]

Step-by-step explanation:

x = 10 \\  \\ y = 10 \sqrt{2} \\  \\  \cos(45)  =  \frac{ \sqrt{2} }{2}

5 0
3 years ago
Rationalise the following: <br> (Root3-1) / (root3+1)
Thepotemich [5.8K]

Answer:

2-\sqrt{3}

Step-by-step explanation:

\begin{aligned}\dfrac{\sqrt{3}-1}{\sqrt{3}+1}\times \dfrac{\sqrt{3}-1}{\sqrt{3}-1} &=\dfrac{(\sqrt{3}-1)(\sqrt{3}-1)}{(\sqrt{3}+1)(\sqrt{3}-1)}\\\\ & =\dfrac{\sqrt{3}\sqrt{3}-\sqrt{3}-\sqrt{3}+1}{\sqrt{3}\sqrt{3}-\sqrt{3}+\sqrt{3}-1}\\\\ & =\dfrac{4-2\sqrt{3}}{2}\\\\ & = 2-\sqrt{3}\end{aligned}

7 0
3 years ago
Consider f(x)=x+7 and g(x)=x^2-1 find (f(g(x))
Nonamiya [84]
F[g(x)]=x^2-1 +7
=x^2+6

Hope this can help.
7 0
3 years ago
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