Given that A = (9,9,2), B = (1,3,5) and C = (5,6,4), find the vector equation of the line through A and B.
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Answer:
The rate of change of the tracking angle is 0.05599 rad/sec
Step-by-step explanation:
Here the ship is traveling at 15 mi/hr north east and
Port to Radar station = 2 miles
Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles
Therefore the ship, port and radar makes a triangle with sides
2, 7.5 and x
The value of x is gotten from cosine rule as follows
x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04
x = 6.25 miles
By sine rule we have
Therefore,
α = Angle between radar and ship α
∴ α = 58.052
Where we put
to get
and differentiate to get
= 3.208 degrees/second = 0.05599 rad/sec.