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Mars2501 [29]
2 years ago
10

Given that A = (9,9,2), B = (1,3,5) and C = (5,6,4), find the vector equation of the line through A and B.

Mathematics
1 answer:
weqwewe [10]2 years ago
3 0

Answer:

It's not C

Step-by-step explanation:

Sorry bud I tried to help you out but i guessed wrong on my test, atleast its not C though:)

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1. Gala Farms sells a 3.5 pound bag of apples
ASHA 777 [7]
The cost per pound for the Gala farms is $1.20 per pound and For the Golden Orchard its $1.05 per pound. Which the Golden Orchard is better since its cheaper and costs 15 cents less.
7 0
3 years ago
An automobile manufacturer has given its car a 46.7 miles/gallon (MPG) rating. An independent testing firm has been contracted t
erastova [34]

Answer:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Step-by-step explanation:

Information given

\bar X=46.5 represent the mean

\sigma=1.1 represent the population standard deviation

n=150 sample size  

\mu_o =46.7 represent the value to verify

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:  

Null hypothesis:\mu = 46.7  

Alternative hypothesis:\mu \neq 46.7  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing we got:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%20%7B%205%20x%20%5E%20%7B%202%20%7D%20-%2029%20x%20-%206%20%7D%20%7B%203%20x%20%5E%20%
olganol [36]

Answer:

Step-by-step explanation:

Vertical Asymptote: x=2Horizontal Asymptote: NoneEquation of the Slant/Oblique Asymptote: y=x 3+23 Explanation:Given:y=f(x)=x2−93x−6Step.1:To find the Vertical Asymptote:a. Factor where possibleb. Cancel common factors, if anyc. Set Denominator = 0We will start following the steps:Consider:y=f(x)=x2−93x−6We will factor where possible:y=f(x)=(x+3)(x−3)3x−6If there are any common factors in the numerator and the denominator, we can cancel them.But, we do not have any.Hence, we will move on.Next, we set the denominator to zero.(3x−6)=0Add 6 to both sides.(3x−6+6)=0+6(3x−6+6)=0+6⇒3x=6⇒x=63=2Hence, our Vertical Asymptote is at x=2Refer to the graph below:enter image source hereStep.2:To find the Horizontal Asymptote:Consider:y=f(x)=x2−93x−6Since the highest degree of the numerator is greater than the highest degree of the denominator,Horizontal Asymptote DOES NOT EXISTStep.3:To find the Slant/Oblique Asymptote:Consider:y=f(x)=x2−93x−6Since, the highest degree of the numerator is one more than the highest degree of the denominator, we do have a Slant/Oblique AsymptoteWe will now perform the Polynomial Long Division usingy=f(x)=x2−93x−6enter image source hereHence, the Result of our Long Polynomial Division isx3+23+(−53x−6)

4 0
2 years ago
Please help!! Is it possible to prove that the triangles are congruent by using the AAS Congruence Theorem?
goldenfox [79]

Answer:

no, there is not enough information to use AAS congruence theorem to prove the triangles are congruent

6 0
2 years ago
Can somebody help?
Tatiana [17]

Answer:

a its the first one

Step-by-step explanation:

because i did the math and i have dont this question before

5 0
3 years ago
Read 2 more answers
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