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Elenna [48]
3 years ago
8

How do I do this?!? Plz help me, I've no clue how to even start!

Mathematics
1 answer:
Anit [1.1K]3 years ago
8 0
You're learning this in middle school????????!!!!!!!!!
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SOMEONE PLEASE HELP ME!!! I REALLY NEED SOME HELP!!!
Lostsunrise [7]

Answer:

A. (1, -2)

Step-by-step explanation:

We can substitute the variables of x and y into the inequality of y < -|x|.

Let's start with A, -2 being y and 1 being x.

-2 < - |1|

The absolute value of 1 is 1, and negating that gets us -1.

-2 < -1

Indeed, -2 is less than -1! So A is a solution to the inequality.

Let's test the rest of them, just in case.

For B:

-1 < -|1|

Absolute value of 1 is 1, negating it is -1.

-1

-1 is EQUAL to -1, not less than it, so is not a solution to the inequality.

Let's try C.

0 < -|1|

Absolute value of 1 is 1, negating it is -1.

0 < -1

0 is GREATER than -1, so that is not a solution to the inequality.

Hope this helped!

4 0
3 years ago
Which elements in a set below are integers?12,-3/4,5,-7,2.24,14/7,9
zhuklara [117]

Answer:

12, 5, -7, 14/7, 9

Step-by-step explanation:

Integers are numbers that are either positive or negative and are whole numbers (no decimals).

4 0
3 years ago
Will What will -3 be in this problem if it replaced the -x?<br> Y= -x+6
Fiesta28 [93]

Answer:

9

Step-by-step explanation:

8 0
3 years ago
Answer number 4 this is due tomorrow
ikadub [295]

Answer:

The next mark should be at (3,-3)

5 0
3 years ago
Which statement is true about this quadratic equation?<br> y=x^(2)-11x+7
Sliva [168]

Answer: <em>This quadratic equation has two real solutions.</em>

<em />

Step-by-step explanation:

y=x^{2} -11x+7\\\\D=(-11)^{2} -4 \cdot 7=121-28=93 \: > 0\\\\x=\dfrac{11 \pm \sqrt{93} }{2}

6 0
2 years ago
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