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Phoenix [80]
3 years ago
13

Trying to understand this

Mathematics
1 answer:
velikii [3]3 years ago
3 0
1 represent 3 days , 2 represent 6 days , 3 represent 9 days , and 4 represent 12 days
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15 more than -8 is:<br><br> can i please have a answer
RoseWind [281]

Answer:

7

Step-by-step explanation:

15+-8=7

4 0
2 years ago
Read 2 more answers
A student ran out of time on a multiple choice exam and randomly guessed the answers for 2 problems. Each problem had 5 answer c
frozen [14]
So if there are 5 choices and only one is correct, there is a 1/5 chance of being correct. since there was 2 questions, you need to multiply 1/5 by 1/5 to get 2/25 of getting both questions correct.

i hope this helps!!
3 0
3 years ago
Find the distance between the points (-7, -10) and (-5, -1)
julsineya [31]
Find the Distance Between Two Points
Use the distance formula to determine the distance between two points.
Exact Form:
√85

Decimal Form:
9.21954445
…
7 0
2 years ago
The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,
uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right).

We need to solve it and obtain an expression for P(t) in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right).

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that k=0.04 and K=500 and the initial condition P(0)=100.

Notice that this equation is separable, then

\frac{dP}{P(1-P/K)} = kdt.

Now, intagrating in both sides of the equation

\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C.

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}.

So,

\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|.

We have obtained that:

-\ln\left| \frac{K-P}{P}\right| = kt +C

which is equivalent to

\ln\left| \frac{K-P}{P}\right|= -kt -C

Taking exponentials in both hands:

\left| \frac{K-P}{P}\right| = e^{-kt -C}

Hence,

\frac{K-P(t)}{P(t)} = Ae^{-kt}.

The next step is to substitute the given values in the statement of the problem:

\frac{500-P(t)}{P(t)} = Ae^{-0.04t}.

We calculate the value of A using the initial condition P(0)=100, substituting t=0:

\frac{500-100}{100} = A} and A=4.

So,

\frac{500-P(t)}{P(t)} = 4e^{-0.04t}.

Finally, as we want the value of t such that P(t)=200, we substitute this last value into the above equation. Thus,

\frac{500-200}{200} = 4e^{-0.04t}.

This is equivalent to \frac{3}{8} = e^{-0.04t}. Taking logarithms we get \ln\frac{3}{8} = -0.04t. Then,

t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325.

So, the population of rats will be 200 after 25 months.

6 0
3 years ago
Write an integer for each situation. 3 miles below sea level u may solve the other ones?
Evgen [1.6K]

"3 miles below sea level" may be written as -3. The negative indicates you are below sea level. Going above sea level means the value would be positive.

"earning 45 dollars" can be written as +45 or simply 45. If you lost 45 dollars, then it would be -45. If you are in debt 45 dollars, then it would be -45.

"moving back 5 spaces" is represented by -5 whereas moving forward 5 spaces is +5 or simply 5.

6 0
3 years ago
Read 2 more answers
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