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EleoNora [17]
3 years ago
5

An amusement park charges a fee of 5$ each time you enter the park .The cost of each ride is 2.50.Which expression shows the cos

t C (in dollars) as a function of the number of rides r you go on at the amusement park during one visit
Mathematics
1 answer:
miss Akunina [59]3 years ago
8 0

Answer:

C(r) = 5 + 2.5r

Step-by-step explanation:

An amusement park charges a fee of 5$ each time you enter the park. The cost of each ride is $2.50.

Therefore, the cost of r number of rides inside the park will be $2.5r.

Hence, the expression that shows the cost C (in dollars) as a function of the number of rides r, I go on at the amusement park during one visit will be  

C(r) = 5 + 2.5r (Answer)

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3 numbers that are greater than 12,000 but less than 13,000
AleksandrR [38]
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Read 2 more answers
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Degger [83]

Let x = pounds of $12 per pound coffee

then

20-x = pounds of $9 per pound coffee

.

12x + 9(20-x) = 10(20)

12x + 180 - 9x = 200

3x + 180 = 200

3x = 20

x = 20/3

x = 6 and 2/3 pounds of $12 per pound coffee

.

Amount of $9 per pound coffee:

20-x = 20-20/3 = 60/3 - 20/3 = 40/3

or

13 and 1/3 pounds of $9 per pound coffee

3 0
3 years ago
Can someone pls help me with this
muminat

Answer:

C f=9

Step-by-step explanation:

isolate f on one side so you subtract 5 from both sides to get 3f=27 and then divide by 3 on each side to get f=9

5 0
3 years ago
Read 2 more answers
Edg vector operations, any help appreciated!
viktelen [127]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: Add \:\: -6 \hat i - 6\hat j \:\:with \:\; Vector \:\; c

____________________________________

\large \tt Solution  \: :

Vector d can be represented as :

\qquad \tt \rightarrow \:  - 2 \hat i - 2 \hat j

Vector c can be represented as :

\qquad \tt \rightarrow \:  4 \hat i + 4\hat j

we have to create vector d from vector c

So, let's assume a vector x, such that sum of vector x and vector c equals to vector d

\qquad \tt \rightarrow \: x + ( 4 \hat i + 4 \hat j) =  - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = -  ( 4 \hat i + 4 \hat j)   - 2 \hat i  - 2 \hat j

\qquad \tt \rightarrow \: x  = (-   4 \hat i  - 2 \hat  i)  + (  - 4 \hat j  - 2 \hat j)

\qquad \tt \rightarrow \: x  = - 6 \hat  i    -6 \hat j

Henceforth, in order to get vector d, we need to add (-6i - 6j) in vector c

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0
2 years ago
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