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Iteru [2.4K]
3 years ago
10

In which type of network can a computer upload and download data at the same time?

Computers and Technology
1 answer:
REY [17]3 years ago
8 0

answer is peer-to-peer


hope this helps

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Which of the following is NOT a reason we use subprograms?
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Answer: A. to add comments to Lines of code

Explanation:

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What is the scope of numC?
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Answer:

local scope which is the entire body of the function/method that it is being used in

Explanation:

The variable numC has a local scope which is the entire body of the function/method that it is being used in, which in this scenario is the passwordMaker method. This is because the variable numC is being used as a parameter variable for that method, meaning that a piece of information is being inputted by when the method is called and saved as the variable numC which is then used by the lines of code inside the method, but cannot be accessed from outside the method thus.

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Trace the evaluation of the following expressions, and give their resulting values. Make sure to give a value of the appropriate
Masja [62]

Answer:

(a)\ 14"."43

(b)\ 0"0"7

(c)\ 2"8 - 2"611

(d)\ 7"(1 + 1)"46

(e)\ "1"23"4"30"7"17

Explanation:

Required

Evaluate each expression

The simple rules to follow are:

(1) All expressions in bracket will be evaluated based on its data type

(2) Divisions will return only integer values

(3) Integers immediately after string values will be concatenated (not added)

So, the results are as follows:

(a)\ 4 + 1 + 9 + "." + (-3 + 10) + 11 / 3

Evaluate till a string is encountered

4 + 1 + 9 = 14

Followed by "."

Then:

(-3 + 10)   = 7

11/ 3 = 3

"." + (-3 + 10) + 11/3 = "."73 -- because expressions after string operations are concatenated.

So, we have:

4 + 1 + 9 + "." + (-3 + 10) + 11 / 3 = 14"."43

(b)\ 8 + 6 * -2 + 4 + "0" + (2 + 5)

Evaluate till a string is encountered

8 + 6 * -2 + 4 =0

"0" + (2 + 5) ="0"7

So, we have:

8 + 6 * -2 + 4 + "0" + (2 + 5) = 0"0"7

(c)\ 1 + 1 + "8 - 2" + (8 - 2) + 1 + 1

Evaluate till a string is encountered

1 + 1 = 2

"8 - 2" + (8 - 2) + 1 + 1 = "8 - 2"611

So, we have:

1 + 1 + "8 - 2" + (8 - 2) + 1 + 1 = 2"8 - 2"611

(d)\ 5 + 2 + "(1 + 1)" + 4 + 2 * 3

Evaluate till a string is encountered

5 + 2 =7

"(1 + 1)" + 4 + 2 * 3 = "(1 + 1)"46 --- multiply 2 and 3, then concatenate

So, we have:

5 + 2 + "(1 + 1)" + 4 + 2 * 3= 7"(1 + 1)"46

(e)\ "1" + 2 + 3 + "4" + 5 * 6 + "7" + (8 + 9)

Since a string starts the expression, the whole expression will be concatenated except the multiplication and the expressions in bracket.

So, we have:

"1" + 2 + 3 + "4" + 5 * 6 + "7" + (8 + 9) = "1"23"4"30"7"17

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Answer:

Which part of the code??

Explanation:

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