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Dmitry [639]
3 years ago
14

Consider the following network: proxy-cache On average there are 35 objects downloaded per second, and the average object size i

s 50,000 bits. What is the traffic intensity on the 2 Mbps access link?
a. 0.035
b. 0.007
c. 0.250
d. 0.875
Computers and Technology
1 answer:
Andrews [41]3 years ago
4 0

Answer:

(d) 0.875 erlangs

Explanation:

In a digital network, the traffic intensity = \dfrac {aL}{R}

where

a = average arrival rate of packets = 35 objects downloaded per second

L is the average packet length = 50,000 bits (e.g. in bits), and

R is the transmission rate = 2 Mbps = 2,000,000 bits per second

Traffic Intensity = \dfrac {aL}{R}=\dfrac {50000 X 35}{2000000}=\dfrac {1700000}{2000000}=0.875

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Answer: Aggressive

Explanation:

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3 years ago
Write a function called mul_time that takes a Time_Elapsed object and a number and returns a new Time_Elapsed object that contai
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# Write a function called mul_time that takes a Time object and a number and

# returns a new Time object that contains the product of the original Time and

# the number.

# Then use mul_time to write a function that takes a Time object that

# represents the finishing time in a race, and a number that represents the

# distance, and returns a Time object that represents the average pace (time

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# Current Status: Complete

class Time(object):

   """ represents the time of day.

   attributes: hour, minute, second"""

time = Time()

time.hour = 3

time.minute = 0

time.second = 0

def time_to_int(time):

   minutes = time.hour * 60 + time.minute

   seconds = minutes * 60 + time.second

   return seconds

def int_to_time(seconds):

   new_time = Time()

   minutes, new_time.second = divmod(seconds, 60)

   time.hour, time.minute = divmod(minutes, 60)

   return time

def mul_time(time, multicand):

   time_int = time_to_int(time) * multicand

   new_time = int_to_time(time_int)

   if new_time.hour > 12:

       new_time.hour = new_time.hour % 12

#    print ("New time is: %.2d:%.2d:%.2d"

#    % (new_time.hour, new_time.minute, new_time.second))

   return new_time

# mul_time(time, 2)

def race_stats(time, distance):

   print ("The finish time was %.2d:%.2d:%.2d"

         % (time.hour, time.minute, time.second))

   print "The distance was %d miles" % (distance)

   average = mul_time(time, (1.0 / distance))

   print ("The average is: %.2d:%.2d:%.2d per mile"

         % (average.hour, average.minute, average.second))

race_stats(time, 3)

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