Answer:
77.6 g are the mass of silver
Explanation:
This is a calorimetry problem, All the heat released by the silver was gained by the water, so the T° has increased.
Q = m . C . ΔT
mass from silver . 0.056 cal/g°C . (26.2°C - 58.5°C) = 100 g . 1 cal/g°C (26.2°C - 24.8°C)
mass from silver . 0.056 cal/g°C .-32.3°C = 100 g . 1 cal/g°C . 1.4°C
mass from silver . -1.8032 cal/g = 140 cal
mass from silver = 140 cal / 1.8032 g/cal
mass from silver = 77.6 g
Answer:
800mL
Explanation:
Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant
P1V1= P2V2
P1 = 2 atm, V1 = 2000mL ,
P2 = 5atm , V2 = ?
2 × 2000 = 5 × V2
Divide both sides by 5
V2 = 4000 ÷ 5
V2 = 800mL
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Newton's F=ma, which means the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)
Explanation:
F = ma, or force is equal to mass times acceleration.
Answer is: 16,56 kJ.
1) m(NH₄Cl) = 5,35g.
m(H₂O) = d(H₂O) · V(H₂O) = 1g/cm³ · 100cm³ = 100g.
ΔT = 25,55°C - 21,79°C = 3,76°C.
Q = m(solution) · C(specific heat capacity of water) ·ΔT.
Q = 105,35g · 4,18 J/g·°C · 3,76°C = 1655,76J.
2) m(NH₄Cl) = 1mol · 53,5g/mol = 53,5g.
m(water) = d(H₂O) · V(H₂O) = 1g/cm³ · 1000cm³ = 1000g.
m(solution) = 1053,5g, ten times more than first solutn.
Q = 10 · 1655,76J = 16557,6J = 16,56 kJ.
