Answer:
Basically an object in motion or at rest will remain that way unless an outside force acts against it.
Explanation:
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia.
The answer is 33.2 moles of a solute is present in 4.00 L of an 8.30 M solution , Option A is correct .
<h3>
What is Molarity ?</h3>
Molarity is defined as the amount of solute (in moles)in per litre of solution.
It is also known as molar concentration of a solution , It is expressed in mol/l
We can rearrange this equation to get the number of moles:
n= M * V
The molarity of solution is 8.3 M and the volume given is 4 litres
the moles will be n = 8.30 * 4 = 33.2 moles
Therefore 33.2 moles of a solute is present in 4.00 L of an 8.30 M solution , Option A is correct .
To know more about molarity
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I think the answer is Density
Answer:
B) -1551 kJ
Explanation:
There are two heat flows in this question.
Heat released by engine + heat absorbed by water = 0
q₁ + q₂ = 0
q₁ + mCΔT = 0
Data:
m = 2.51 kg
C = 3.41 J°C⁻¹g⁻¹
T_i = 23.8 °C
T_f =205 °C
Calculations:
(a) ΔT
ΔT = 205 °C - 23.8 °C = 181.2 °C
(b) q₂
q₂ = mCΔT = 2510 g × 3.41 J·°C⁻¹g⁻¹ × 181.2 °C = 1.551× 10⁶ J = 1551 kJ
(c) q₁
q₁ + 1551 kJ = 0
q₁ = -1551 kJ
Answer:
<u>The half-reaction that occurs on the anode of an electrolytic cell is called oxidation.
</u>
This can easily be depicted by a chemical reaction as such <u>"Zn(s) = Zn2+ (aq) + (2e-)"
</u>
While, the Zinc in this reaction loses two elections. Hence copper gains those electrons and becomes solid.
<em>These reactions occurring on the anode are called positive reactions.
</em>
While the reaction that occurs on the cathode is called reduction. This reaction can be represented by this equation "<u>Cu2+ (aq) + 2e- = Cu(s)</u>".
<u>These non-spontaneous reactions occurring in an electrolytic cell together are called redox reactions. These generate electrical energy.</u>
