You could check if their cells had a nucleus or not. If it did it would be a eukaryote, if it did not then it would be a prokaryote.
That’s some hard stuff what grade are you in im going to find the answer really fast hold on
Answer:
The standard enthalpy of combustion of solid urea ((CO(NH2)2) is -632 kJ mol-1 at 298 K and its standard molar entropy is 104.60 J K-1 mol-1
Explanation:
Answer:
6.1 cm³
Explanation:
To solve this problem we first need to keep in mind <em>Archimedes' principle</em>:
- The volume of water (or any fluid) displaced by a submerged object is equal to the object's volume.
With that in mind we <u>calculate the volume of the granite piece in mililiters</u>:
- Volume displaced = 47.6 mL - 41.5 mL = 6.1 mL
- Volume of the granite piece = 6.1 mL
Given that one cubic centimeter is equal to one mililiter, the volume of the granite piece in cm³ is 6.1 cm³.
