Which element is present in every organic compound?

Assume that helium behaves as an ideal monatomic gas. If 2 moles of helium undergo a temperature increase of 100 k at constant p

Helga [31]

4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.

<h3>What are Noble Gases ?</h3>

The noble gases are helium, argon, krypton, xenon, and radon, in order of their mass.

They are called noble gases because they are so majestic that they do not react with anything in general.

The work done can be calculated by the formula

Q=n Cp ΔT

Cp= ( 1+ f/2)R

R= 8.3144598 J. mol-1.

Cp = (1+3/2) * 8.314

Cp = 5*8.314/2

Q= 2 * 5 *8.314 *100/2

Q = 4157 J

Therefore 4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.

To know more about Noble Gas

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3 0

2 years ago

A student dissolves of 15 g aniline in of a solvent with a density of . The student notices that the volume of the solvent does

VikaD [51]

The given question is incomplete. The complete question is ;

A student dissolves of 15 g aniline in 200 ml of a solvent with a density of 1.05 g/ml. The student notices that the volume of the solvent does not change when the aniline dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits.

Answer: The molarity is 0.81 M and molality is 0.82 m

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute

$V_s$ = volume of solution in ml = 200 ml

${\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol$

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{0.16\times 1000}{200}=0.81M$

Thus molarity is 0.81 M

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molarity=\frac{n\times 1000}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in g

${\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{15g}{93g/mol}=0.16mol$

Mass of solution = $Density\times Volume=1.05g/ml\times 200ml=210g$

mass of solvent = mass of solution - mass of solute = (210 - 15) g = 195 g

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.16\times 1000}{195g}=0.82mole/kg$

Therefore, the molality of solution is 0.82m

3 0

3 years ago

Which statement is not included in John Dalton's modern theory of the atom?

Harman [31]

Answer:

atoms of different elements combine and form new elements

5 0

3 years ago

CAN SOMEONE HELP ME IN ONE CHEM QUESTION PLEASE

Evgesh-ka [11]

What's the question? See if I can be of any help.

7 0

3 years ago

How would you explain the path of alpha particles in relation to each subatomic particle in the plum pudding model?

forsale [732]

In the plum pudding model, alpha particles were expected to pass through the foil at different angles and some of them reflected. They realized that there are positive charge atom because it repels. So the plum pudding was replaced by the nuclear model of atom.

7 0

3 years ago