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3 years ago

A high gold-quartz ore contains is 0.25% gold by mass. how many grams of gold are in 1.25 tons of this ore?

1 answer:

8 0

Assuming a ton is 2,000 lbs use the following equation to figure out how many grams of gold by mass there is:
***NOTE*** if this is a metric ton then the conversion will be 1 metric ton = 1000 kg

1.25 tons x 2000 lb/ton = 2,500 lbs
2,500 lbs x .4535 kg/lbs = 1133.75kg x 1000 g/kg = 1,133,750 g
IF METRIC TON then 1.25 x 1000 = 1250 x 1000g/kg = 1,250,000 g

because it says 0.25% and a pecent is out of a 100, you must divide that percentage by 100
use fraction of: 0.25%/100 = 0.0025

(easy way to think about this is if it were 50% gold by mass, then you would multiple the total tonnage by .5 (50/100 = .5), so 0.25% = 0.0025)

1,113,750g x .0025 = 2834 g of gold

if metric ton 1,250,000 x 0.0025 = 3125 g of ogld

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A cylinder contains 3.1 L of oxygen at 300 K and 2.7 atm. The gas is heated, causing a piston in the cylinder to move outward. T

zubka84 [21]

Answer: The moles of gas present in the cylinder is 0.34 moles.

Explanation:

Given: $P_{1}$ = 2.7 atm, $V_{1}$ = 3.1 L, $T_{1}$ = 300 K

$P_{2}$ = ?, $V_{2}$ = 9.4 L, $T_{2}$ = 610 K

Formula used to calculate the final temperature is as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Substitute the values into above formula as follows.

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{2.7 atm \times 3.1 L}{300 K} = \frac{P_{2} \times 9.4 L}{610 K}\\P_{2} = \frac{5105.7}{2820} atm\\= 1.81 atm$

Now, moles present upon heating the cylinder are as follows.

$P_{2}V_{2} = n_{2}RT_{2}\\1.81 atm \times 9.4 L = n_{2} \times 0.0821 L atm/mol K \times 610 K\\n_{2} = \frac{17.014}{50.081} mol\\= 0.34 mol$

Thus, we can conclude that moles of gas present in the cylinder is 0.34 moles.

6 0

3 years ago

Determine the latitude and longitude of the location A

malfutka [58]

Answer:

Latitude: $30\° N$

Longitude: $45\° W$

Explanation:

Lets begin by explaining the meaning of latitude and longitude as geogrephical coordinates:

Latitude is the angular distance between the equatorial line, and a specific point on the Earth. It is measured in degrees and is represented according to the hemisphere in which the point is located, which can be north or south latitude.

In this sense latitude $0\°$ refers to the equatorial line that divides the Earth in two hemispheres (North and South).

Longitude represents the specific east–west position of a point on the Earth's surface, being longitude $0\°$ the prime meridian or Greenwich meridian.

So, according to the figure, where the model of the Earth is divided by latitude lines separated by $10\°$ and the longitude lines separated by $15\°$ ; we only have to count the lines from the equator to the line where the point A is, and count the lines fromo the Prime meridian to the line where point A is located.

Hence, point A location is:

Latitude: $30\° N$

Longitude: $45\° W$

5 0

3 years ago

I will give brainliest. If you burn the carbon in limited air, the reaction is

Fynjy0 [20]

This reaction is different in that the carbon undergoes an incomplete combustion as opposed to complete combustion where carbon is fully oxidized. A caveat: incomplete combustion products in general can be difficult to predict without sufficient information, as it's not uncommon to obtain a mixture of different products.

Here, we are told that solid carbon is burned in limited air to produce a gas. I am presuming that, in the equation that's given, the "0" represents a blank where you must fill in a chemical symbol. In this case, our equation would be: 2C(s) + O₂(g) → 2CO(g).

There is not enough information here to provide the numerical answers to the two questions. From the words in the question (e.g., "is different" and "this time"), it would seem that this question is an excerpt from a larger or preceding question where specific numbers had been provided or computed.

However, it's possible to make some general observations on how one may go about answering these questions if one had more information.

Since we're to assume that oxygen is the limiting reagent, if one is given the amount of solid carbon (either in mass, moles, or number of atoms), it's possible to determine the moles of CO(g) that's produced since C and CO have an equal stoichiometric ratio. So, for example, if one burns 2 moles of C(s), then 2 moles of CO(g) would be produced.

But, there is still not enough information to compute the volume of CO gas if this is the line of questioning. We don't know, for instance, the temperature or pressure of the reaction conditions. In fact, the only way it would be possible to answer this would be if you were given beforehand a conversion factor that relates the volume of CO(g) to its quantity (e.g., to assume that one mole of gas occupies x liters).

As for the second question, this would depend on what you know about the quantity of the C(s) reacted and/or the quantity (or volume, from question a) of CO(g) produced. If you can get the number of moles of C(s) reacted or CO(g) produced, the number of moles of O₂(g) used up: It would be half the number of moles of C(s) reacted or half the number of moles of CO(g) produced). Again, it's impossible to determine the volume of O₂(g) using just the information provided here, so I suspect that you must have further information relating gas quantity to volume. As we did with CO(g), the volume of O₂(g) used up can be found using whatever conversion factor you have.

If you have any further information or questions, please feel free to follow up.

6 0

2 years ago

which of the following is not part of the big bang theory?A. In the beginning the universe was too hot for atoms to exist. B. As

erastovalidia [21]

A.) In the beginning the universe was too hot for atoms to exist.

Because choice b,c,and d are all part of the big bang theory.

8 0

3 years ago

Read 2 more answers

To heat 1g of water by 1c requires

Pie

C, because specific heat is measured in Joules/grams°C