The highest energy occupied molecular orbital in the C-C bond of the C₂ molecule is 2pπ orbitals.
<h3>What is Molecular Orbital Theory?</h3>
According to this theory,
- Molecular orbitals are formed by intermixing of atomic orbitals of two or more atoms having comparable energies
- The number of molecular orbitals formed is equal to the number of atomic orbitals combined.
- The shape of molecular orbitals formed depends on the type of atomic orbitals combined
- Only atomic orbitals having comparable energies and the same orientation can intermix
- Bonding M.O. is formed by the additive effect of atomic orbitals and thus, has lower energy and high stability.
- Antibonding M.O. is formed by the subtractive effect of atomic orbitals and thus, has higher energy and low stability.
- Bonding M.O. is represented by
while Antibonding M.O. is represented by 
Molecular Orbital Diagram of C₂
Learn more about Molecular Orbital Theory:
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For example, the atomic mass of an oxygen atom is 16.00 amu; that means the molar mass of an oxygen atom is 16.00 g/mol. Further, if you have 16.00 grams of oxygen atoms, you know from the definition of a mole that your sample contains 6.022 x 10^23 oxygen atoms.
Answer:
Si, Sn, Cs
Explanation:
Atomic no. Atomic radius
Silicon Si_______14___________0.117
Tin Sn______50___________0.140
cesium Cs______55___________0.262
Silicon is the smallest among these
2NaCN(s) + H₂SO₄(aq) --> Na₂SO₄(aq) + 2HCN(g)
The molar ratio between NaCN : HCN is 2:2 or 1:1
Mass of HCN = 16.7 g
Molar mass of HCN = 1 + 12 + 14 = 27 g/mol
Molar mass of NaCN = 49 g/mol
Therefore, the mass of NaCN is
16.7 g of HCN x 49 g/mol of NaCN / 27 g/mol of HCN = 30.3 grams of NaCN
Therefore, 30.3 grams of NaCN gives the lethal dose in the room.
Answer:
The answer to your question is 25.2 g of acetic acid.
Explanation:
Data
[Acetic acid] = 0.839 M
Volume = 0.5 L
Molecular weight = 60.05 g/mol
Process
1.- Calculate the number of moles of acetic acid
Molarity = moles / volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = (0.839)(0.5)
-Result
moles = 0.4195
2.- Calculate the mass of acetic acid using proportions and cross multiplications
60.05 g ----------------------- 1 mol
x ----------------------- 0.4195 moles
x = (0.4195 x 60.05) / 1
x = 25.19 g
3.- Conclusion
25.2 g are needed to prepare 0.500 L of Acetic acid 0.839M
