Answer:
Oxidation state shows the total number of electrons which have been removed from an element (a positive oxidation state) or added to an element (a negative oxidation state) to get to its present state
Explanation:
Matter can be categorized into substances and mixtures.
Matter is anything that has mass and occupies spaces.
Substances are distinct matter with the following properties:
- All parts are the same throughout i.e homogeneous
- Their composition is definite
- They cannot be easily separated or broken down into simpler substances by physical means
- Separation by physical means is not easy
- They have a unique set of physical properties.
Mixtures have the following properties:
- Their composition is indefinite i.e they consist of two or more elements and/or compounds in any proportion by mass
- Their constituents retains their identity
- They can easily be separated by physical means
- They have a broad range of physical properties.
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The moles of ammonium nitrate needed to dissolve 0.35 moles
The moles of water that will react is 0.35 moles as due to ratio
so mass of water will be 0.35 x 18=6.3g
MASS OF WATER WILL BE 6.3 g
Answer:
These two are equivalent and valid:
Explanation:
The molecular superscripts for each atom in the <em>molecular formula</em> are determined by the number of times that the mass of the<em> empirical formula</em> is contained in the<em> molar mass</em>.
<u />
<u>1. Determine the mass of the empirical formula:</u>
:
Atomic masses:
- O: 15.999g/mol
- C: 12.011g/mol
- N: 14.007g/mol
- Cl: 35.453g/mol
Total mass:
- 15.999g/mol + 12.011g/mol + 14.007g/mol + 35.453g/mol = 77.470g/mol
<u />
<u>2. Divide the molar mass by the mass of the empirical formula:</u>
- 232.41g/mol / 77.470g/mol = 3
<u>3. Multiply each superscript of the empirical formula by the previous quotient: 3</u>
Or:
You might also write CN as a group:
Answer:
30.1 g NaCl
Explanation:
Your first conversion is converting grams NaOH to moles of NaOH using its molar mass (39.997 g/mol). Then, use the mole ratio of 1 mol NaCl for every 1 mol NaOH to get to moles of NaCl. Then finally multiply by the molar mass of NaCl (58.44 g/mol) to get grams of NaCl.
20.6 g NaOH • (1 mol NaOH / 39.997 g NaOH) • (1 mol NaCl / 1 mol NaOH) • (58.44 g NaCl / 1 mol NaCl) = 30.1 g NaCl
