The answer to your question is option b because opposite angles in a quadrilateral are equal to one another

It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>

</span><span>In notation we write respectively
</span>

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence

Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²

That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers 
Answer:
x = 3
Step-by-step explanation:
3(x - 4) = -3
Divide by 3
3/3(x - 4) = -3/3
x-4 = -1
Add 4 to each side
x-4+4 = -1+4
x = 3
Answer:
14:9
Step-by-step explanation:
you cant simplify so just put : in between the numbers and boom! ur ratio is 14 to 9 or 14:9
hope this helps :D
Answer:
suree thx
Step-by-step explanation: