Question

Hal has 20 pieces of candy in a bag: 12 mint sticks, 5 jelly treats, and 3 fruit tart chews. If he eats one piece every 8 minutes, what is the probability his first two pieces will both be mint sticks?

Answer 1

Use the AND operation so 12/20 x 11/19 total candies will be reduced to 19 for 2nd mint bcz he is not replacing them if first was mint then chances of second being mint is 11 so 132/380 which can be further simplified

Answer 2

Answer: $\dfrac{33}{95}$

Step-by-step explanation:

Given : Number of pieces of candy in the bag =20

Number of pieces of mint sticks =12

If he eats one piece every 8 minutes, then the number of ways that he eats mint sticks =$12\times11=132$

The total number of ways that he eats any two pieces of candies=$20\times19=380$

Now, the probability his first two pieces will both be mint sticks :-

$\dfrac{132}{380}=\dfrac{33}{95}$

Hence, the probability his first two pieces will both be mint sticks =  $\dfrac{33}{95}$