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dmitriy555 [2]
3 years ago
8

The Perimeter of rectangle DEFG is 120, ED=X, and FE=4x. What is the value of x?

Mathematics
2 answers:
Mazyrski [523]3 years ago
6 0

Perimeter=120

ED=x (length)

FE=4x (breadth)

Perimeter of rectangle= 2(l+b)

Given,

2(x+4x)=120

2x+8x=120

10x=120

x=120÷10

x=12

Therefore, value of x is 12

tensa zangetsu [6.8K]3 years ago
6 0

Answer: 12

<u>Step-by-step explanation:</u>

You are given that perimeter = 120, length (FE) = 4x, and width (ED) = x

 P  =    2L  + 2w    (P = perimeter, L = length, w = width)

120 = 2(4x) + 2(x)

120 =   8x   +  2x

120 =       10x

<u>÷10 </u>    <u>   ÷10    </u>

12  =          x

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