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Georgia [21]
2 years ago
9

The gravitational force between two volleyball players is 3.9 × 10^-7 N . If the kasses of the players are 63 kg and 78 kg, what

is their separation?​
Physics
1 answer:
N76 [4]2 years ago
3 0

Answer:

I honestly have no idea bro.

Explanation:

Hope that helps have a great night.

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Galileo _____.
AnnZ [28]

Answer:

friction help to slow motion in other word it oppose motion, but in a frictionless environment object would move with difficult stopping point.

5 0
3 years ago
Read 2 more answers
A student is asked to determine the work done on a block of wood when the block is pulled horizontally using an attached string.
Lerok [7]

Answer:

D. Graphing the force as a function of distance and calculating the area under the curve.

Explanation:

5 0
3 years ago
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When an RL circuit is connected to a battery, which is true about its initial and final states?
zubka84 [21]

Answer:A

Explanation:

In R-L circuit current is given by

i=i_0\left [ 1-e^{\frac{-t}{L/R}}\right ]

where i=current at any time t

i_0=maximum\ current

R=resistance

L=Inductance

at t=0 e^{\frac{-t}{L/R}} approaches to 1

therefore i=i_0\left [ 1-1\right ]

i=0

when t approaches to \infty,  e^{\frac{-t}{L/R}} approaches to zero

thus i=i_0

thus we can say that initially circuit act as broken wire with zero current

and it increases exponentially with time and act as ordinary connecting wire

7 0
3 years ago
The valu
natulia [17]

Answer:

\% Error = 2.6\%

Explanation:

Given

x: 1.54, 1.53, 1.44, 1.54, 1.56, 1.45

Required

Determine the percentage error

First, we calculate the mean

\bar x = \frac{\sum x}{n}

This gives:

\bar x = \frac{1.54+ 1.53+ 1.44+ 1.54+ 1.56+ 1.45}{6}

\bar x = \frac{9.06}{6}

\bar x = 1.51

Next, calculate the mean absolute error (E)

|E| = \sqrt{\frac{1}{6}\sum(x - \bar x)^2}

This gives:

|E| = \sqrt{\frac{1}{6}*[(1.54 - 1.51)^2 +(1.53- 1.51)^2 +.... +(1.45- 1.51)^2]}

|E| = \sqrt{\frac{1}{6}*0.0132}

|E| = \sqrt{0.0022}

|E| = 0.04

Next, calculate the relative error (R)

R = \frac{|E|}{\bar x}

R = \frac{0.04}{1.51}

R = 0.026

Lastly, the percentage error is calculated as:

\% Error = R * 100\%

\% Error = 0.026 * 100\%

\% Error = 2.6\%

4 0
3 years ago
What is/are the energy transformation(s) that take place when using a wind turbine to generate usable energy?
Cerrena [4.2K]

Answer:

the answer is C

Explanation:

C) friction - mechanical - electrical

4 0
3 years ago
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