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ELEN [110]
3 years ago
5

Wan and Nurul sat on a see-saw. The see-saw is imbalanced because Wan’s mass is 45 kg while Nurul’s mass is only 30 kg. Suggest

how Nurul can balance the see-saw.
Physics
1 answer:
Alex Ar [27]3 years ago
5 0

We have that the see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

From the Question we are told that

Wan’s mass is M_w=45 kg

Nurul’s mass is M_n= 30 kg.

Generally

The Will be balance when the weight on both sides of the see-saw are equal

M_w=M_n+x

45=30+x

x=45-30

x=15kg

In conclusion

The see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

For more information on this visit

brainly.com/question/22255610

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Answer:

A) increase.

Explanation:

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        C = \frac{Q}{V} (1)

  • At the same time, we can show (applying Gauss' Law to the surface of one of the plates), that the capacitance of a parallel-plate capacitor (with a dielectric of air), can be written as follows:

       C = ε₀*A / d  (2)

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       C =\frac{\epsilon_{0}*\kappa*A}{d} (3)

  • If the capacitor, once charged, is disconnected from the battery, charge must keep the same.
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mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan
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Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, v_e, for the planet is v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }

Where;

v_e = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, M_E

r = The radius of the planet = 3 × The radius of Earth, R_E

The escape velocity for Earth, v_e_E, is therefore given as follows;

v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }

\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } =  \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E

v_e = 16 × v_e_E

Given that the escape velocity for Earth, v_e_E ≈ 11,186 m/s, we have;

The escape velocity on the planet = v_e ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0
3 years ago
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