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ELEN [110]
2 years ago
5

Wan and Nurul sat on a see-saw. The see-saw is imbalanced because Wan’s mass is 45 kg while Nurul’s mass is only 30 kg. Suggest

how Nurul can balance the see-saw.
Physics
1 answer:
Alex Ar [27]2 years ago
5 0

We have that the see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

From the Question we are told that

Wan’s mass is M_w=45 kg

Nurul’s mass is M_n= 30 kg.

Generally

The Will be balance when the weight on both sides of the see-saw are equal

M_w=M_n+x

45=30+x

x=45-30

x=15kg

In conclusion

The see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

For more information on this visit

brainly.com/question/22255610

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The unit for measuring electric power is the
bazaltina [42]
C.) The measuring unit of "Electrical Power" is "Watt"

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4 0
3 years ago
a plane travels 204 km, northeast in 15.0 minutes. It also increases elevation by 1.6 km, upward in the same amount of time. Wha
LUCKY_DIMON [66]

Answer:

230 m/s northeast, 1.8 m/s up

Explanation:

204 kilometres = 204000 metres

15.0 minutes = 900 seconds

Velocity = Distance / Time

= 204000 / 900

= 230 m/s northeast (to 2 sf.)

1.6km = 1600 metres

Velocity = 1600 / 900

= 1.8 m/s up (to 2 sf.)

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5 0
3 years ago
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The half-life of the reaction gets shorter as the initial concentration is increased. True or False
Art [367]

True

The half-life isn’t applicable to a first order reaction because it does not rely on the concentration of reactant present. However the 2nd order reaction is dependent on the concentration of the reactant present.

The relationship between the half life and the reactant is an inverse one.

The half life is usually reduced or shortened with an increase in the concentration and vice versa.

3 0
3 years ago
A ball is dropped from a height of 23.5 meters. Assuming no air resistance, how many seconds will it take the ball to hit the
Alex Ar [27]

Answer:

About 2.19 seconds

Explanation:

d=v_ot+\dfrac{1}{2}at^2

Since the ball is dropped from rest, there is no initial velocity, and you can write the following equation:

23.5=\dfrac{1}{2}(9.8)t^2 \\\\t^2\approx 4.79 \\\\t\approx 2.19s

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8 0
2 years ago
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If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?
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By using the combined gas law which says that P1V1/T1 = P2V2/T2, assuming constant pressure, the volume at the required temperature can be obtained.((0.002 m3)(50+273.15))/(20+273.15) = volume 2 at 50 degrees C.
This gives the answer 0.0022048 m3
5 0
3 years ago
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