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ELEN [110]
3 years ago
5

Wan and Nurul sat on a see-saw. The see-saw is imbalanced because Wan’s mass is 45 kg while Nurul’s mass is only 30 kg. Suggest

how Nurul can balance the see-saw.
Physics
1 answer:
Alex Ar [27]3 years ago
5 0

We have that the see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

From the Question we are told that

Wan’s mass is M_w=45 kg

Nurul’s mass is M_n= 30 kg.

Generally

The Will be balance when the weight on both sides of the see-saw are equal

M_w=M_n+x

45=30+x

x=45-30

x=15kg

In conclusion

The see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

For more information on this visit

brainly.com/question/22255610

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When a current is passed through plasma and that current is increased will the temperature of the plasma increase . if it does t
Delicious77 [7]

The temperature of the plasma will increase as current is passed through it.

<h3>Meaning of Current and temperature</h3>

Current can be defined as a flow of charged particles through a medium and the particles includes: electrons or ions.

Temperature is the degree of hotness or coldness experienced by a material.

The more current passes through the plasma the more energy is induced making the particles to move faster which in turns causes temperature to increase and reducing the resistance of the plasma.

In conclusion, The current causes temperature to increase and this reduces the resistance.

Learn more about current: brainly.com/question/1100341

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6 0
2 years ago
SOMEONE PLEASE HELP ME ASAP PLEASE!!!! SIGNIFICANT DIGITS!!!!!! THE ANSWER IS NOT −16.422​
Aleks04 [339]

Explanation:

What exactly are u looking for?

7 0
3 years ago
Read 2 more answers
To meet a U.S. Postal Service requirement, employees' footwear must have a coefficient of static friction of 0.5 or more on a sp
motikmotik

Answer:

0.79 s

Explanation:

We have to calculate the employee acceleration, in order to know the minimum time. According to Newton's second law:

\sum F_x:f_{max}=ma_x\\\sum F_y:N-mg=0

The frictional force is maximum since the employee has to apply a maximum force to spend the minimum time. In y axis the employee's acceleration is zero, so the net force is zero. Recall that f_{max}=\mu N

Now, we find the acceleration:

\mu N=ma_x\\\mu mg=ma_x\\a_x=\mu g\\a_x=0.83(9.8\frac{m}{s^2})\\a_x=8.134\frac{m}{s^2}

Finally, using an uniformly accelerated motion formula, we can calculate the minimum time. The employee starts at rest, thus his initial speed is zero:

x=v_0t+\frac{1}{2}a_xt^2\\2x=a_xt^2\\t=\sqrt{\frac{2x}{a}}\\t=\sqrt{\frac{2(3.2m)}{8.134\frac{m}{s^2}}}\\t=0.79 s

8 0
3 years ago
A note of frequency 200Hz has a velocity of 400m/s. what is the wavelength of the note​
Xelga [282]

Answer:

\huge\boxed{\sf \lambda = 2 m}

Explanation:

<h3><u>Given data:</u></h3>

Frequency = f = 200 Hz

Velocity = v = 400 m/s

<h3><u>Required:</u></h3>

Wavelength = λ = ?

<h3><u>Formula:</u></h3>

v = fλ

<h3><u>Solution:</u></h3>

Put the givens in the formula

400 = (200)λ

Divide 200 to both sides

400/200 = λ

2 m = λ

λ = 2 m

\rule[225]{225}{2}

8 0
2 years ago
If the box weighs 40 newtons and is lifted a distance of 2 meters, how much work is done on the box?
Zarrin [17]

Answer:

The work done on the box is 80 J.

Explanation:

Given that,

Weight of box = 40 N

Distance = 2 meter

We need to calculate the work done

Using formula of work done

W=F\times x

W=mg\times x

Where, x = distance

mg = weight

Put the value into the formula

W=40\times2

W= 80\ Nm

W=80\ J

Hence, The work done on the box is 80 J.

5 0
3 years ago
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