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RideAnS [48]
3 years ago
5

A rock slides down from A to B along the inside surface of a frictionless hemispherical bowl. As the rock slides, mechanical ene

rgy is conserved (ignoring air resistance) because: (Mark all that apply.) Group of answer choices the bowl is hemispherical in shape. the normal force on the rock is balanced by the centrifugal force. the normal force on the rock is balanced by the centripetal force. the normal force on the rock acts perpendicular to the bowl's surface. the rock's acceleration is perpendicular to the bowl's surface. NONE of the other choices.
Physics
1 answer:
DIA [1.3K]3 years ago
6 0

Answer:

the normal force on the rock acts perpendicular to the bowl's surface.

Explanation:

As we know that Normal force is the reaction force of two contact surfaces which always act perpendicular to the contact surfaces

Here we know that the rock is moving inside the bowl

So Normal force on the rock must perpendicular to the surface of the bowl which always passes through the center of the bowl.

Since the rock is moving in vertical plane so it must have two acceleration

1) Tangential acceleration which will increase the magnitude of the speed along the tangential path

2) Centripetal acceleration which will change the direction of the rock

So here only correct option will be

the normal force on the rock acts perpendicular to the bowl's surface.

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What could you do to decrease the rate at which salt dissolves in water?
kotykmax [81]

Answer:

use hot water

Explanation:

hot water helps dissolve things faster

3 0
2 years ago
Match these terms with the correct examples.
posledela
1. liquid solution to a. oceans
2. gaseous solution to b. clouds
Not sure about 3 and 4.
3 might be oxygen but I think that's 5. element.

Hope this helps, not sure about water and air though.
4 0
3 years ago
Read 2 more answers
A motorboat traveling on a straight course slows
never [62]

Answer:

2.572 m/s²

Explanation:

Convert the given initial velocity and final velocity rates to m/s:

  • 65 km/h → 18.0556 m/s
  • 35 km/h → 9.72222 m/s

The motorboat's displacement is 45 m during this time.

We are trying to find the acceleration of the boat.

We have the variables v₀, v, a, and Δx. Find the constant acceleration equation that contains all four of these variables.

  • v² = v₀² + 2aΔx

Substitute the known values into the equation.

  • (9.72222)² = (18.0556)² + 2a(45)
  • 94.52156173 = 326.0046914 + 90a
  • -231.4831296 = 90a
  • a = -2.572

The magnitude of the boat's acceleration is |-2.572| = 2.572 m/s².

3 0
3 years ago
How is position time and motion related
rusak2 [61]
When you make a motion you change position over time.
5 0
3 years ago
A basketball player passes a ball to a teammate at a velocity of 6 m/s. The ball has a mass of 0.51 kg. If the original player h
Vilka [71]

We can solve the problem by using conservation of momentum.

The player + ball system is an isolated system (there is no net force on it), therefore the total momentum must be conserved. Assuming the player is initially at rest with the ball, the total initial momentum is zero:

p_i = 0

The total final momentum is:

p_f = p_p + p_b

where p_p is the momentum of the player and p_b is the momentum of the ball.

The momentum of the ball is: p_b = mv=(0.51 kg)(6 m/s)=3.06 kg m/s

While the momentum of the player is: p_p = Mv_p, where M=59 kg is the player's mass and vp is his velocity. Since momentum must be conserved,

p_f = p_i = 0

so we can write

p_f = Mv_p + p_b =0

and we find

v_p = -\frac{p_b}{M}=-\frac{3.06 kg m/s}{59 kg}=-0.052 m/s

and the negative sign means that it is in the opposite direction of the ball.

8 0
3 years ago
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