A rock slides down from A to B along the inside surface of a frictionless hemispherical bowl. As the rock slides, mechanical ene
1 answer:
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Solution :
Given :
M = 0.35 kg
Total mechanical energy = constant
or
But and
Therefore, potential energy at the top = kinetic energy at the bottom
(h = 35 cm = 0.35 m)
= 2.62 m/s
It is the velocity of M just before collision of 'm' at the bottom.
We know that in elastic collision velocity after collision is given by :
here,
∴
= 0.33 m/s
Therefore, velocity after the collision of mass M = 0.33 m/s