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3 years ago

What is the correct factorization of x² - 11x + 18?

Mathematics

1 answer:

boyakko [2]3 years ago

8 0

C because I did the math on an app so it’s right

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What is the sum of 1,015 and 119<br> a. 896<br> b. 1,134<br> c. 1,224<br> d. 1,314

Julli [10]

b. 1134

1015

0119

1134

I hope this helps!

6 0

3 years ago

Read 2 more answers

there are 2 numbers that are twice as far from 23 as they are from 38. Those two numbers are? QUICKK PLS

sergeinik [125]

Answer:

53&8

Step-by-step explanation:

38-23=15

23+15+15=53

23-15=8

5 0

2 years ago

A speed walker covered 4 1/2 mi in 3/4 hour. How far will he walk in 3/4 hour if he walks

Pavel [41]

Answer:

A=27/4 B=2.25

Step-by-step explanation:

4 and 1/2 also equals 18/4.

18/4+1/2(18/4)=18/4+9/4

18+9=27

Answer is 27/4

B)=4.5/2=2.25

4 0

3 years ago

Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive

PtichkaEL [24]

Looks like the PMF is supposed to be

$\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}$

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

$\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65$

Next,

$\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25$

$\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5$

$\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5$
$\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}$

If $Y=X^2+1$ , then $X^2=Y-1\implies X=\sqrt{Y-1}$ , where we take the positive root because we know $X$ can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that $Y$ can take on the values $1^2+1=2$ , $2^2+1=5$ , and $5^2+1=26$ . At these values of $Y$ , we would have the same probability as we did for the respective value of $X$ . That is,

$\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}$

Part (5) is incomplete, so I'll stop here.

8 0

3 years ago

What is the slope of the line through the points (0, 0) and (2, 6)

EleoNora [17]

For this problem, you would use the slope formula, or m=(y2-y1)/(x2-x1). So, let's put in what we know.

The x's and y's correspond with our coordinates. So let's plug that in:

m=(6-0)/(2-0)
m=(6)/(2)
m=3

So, the slope of your line is 3.

6 0

3 years ago