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DiKsa [7]
3 years ago
6

The escape speed from an object is v2 = 2GM/R, where M is the mass of the object, R is the object's starting radius, and G is th

e gravitational constant 6.67 × 10-11 m3 kg-1 s-2. What is the approximate escape speed, in km/s, from the Solar System starting from an orbit at 1.0 AU? In this case, the mass of the Sun, 2.3e+30 kg, can be used as the mass of the Solar system
Physics
1 answer:
Rom4ik [11]3 years ago
6 0

Answer:

Approximate escape speed = 45.3 km/s

Explanation:

Escape speed

        v=\sqrt{\frac{2GM}{R}}

Here we have

   Gravitational constant = G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²

   R = 1 AU = 1.496 × 10¹¹ m

   M = 2.3 × 10³⁰ kg

Substituting

    v=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 2.3\times 10^{30}}{1.496\times 10^{11}}}=4.53\times 10^4m/s=45.3km/s

Approximate escape speed = 45.3 km/s

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