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Vesnalui [34]
3 years ago
7

Luke,kira and ali each served 2 thirds of their own cake. Each cake was the same size, but luke served 4 slices, kira served 6 s

lices, and ali served 8 slices. How is this possible? Enter your awnsers in the boxes to complete the solution
Mathematics
1 answer:
agasfer [191]3 years ago
5 0

Answer:

The whole slices of Luke,kira and Ali are 6, 9 and 12. So it is possible.

Step-by-step explanation:

Given:

Luke,kira and ali each served 2 thirds of their own cake. Each cake was the same size, but luke served 4 slices, kira served 6 slices, and Ali served 8 slices.

Now, to find how is this possible.

Let the whole slices of cake be x.

Luke served  \frac{2}{3}  of his cake which are 4 slices.

So, the whole slices of cake of Luke is:

\frac{2}{3} \ of\ x=4

\frac{2}{3} \times x=4

Multiplying both sides by 3 we get:

2\times x=12

Dividing both sides by 2 we get:

x=6.

Thus, whole slices of Luke's cake is 6.

Kira served \frac{2}{3}  of her cake which are 6 slices.

So, the whole slices of Kira's cake is:

\frac{2}{3} \ of\ x=6

\frac{2x}{3} =6

Multiplying both sides by 3 we get:

2x=18

Dividing both sides by 2 we get:

x=9.

Therefore, whole slices of KIra's cake is 9.

Now, Ali served \frac{2}{3}  of her cake which are 8 slices.

So, the whole slices of Ali's cake is:

\frac{2}{3} \ of\ x=8

\frac{2x}{3} =8

Multiplying both sides by 3 we get:

2x=24

Dividing both sides by 2 we get:

x=12.

Hence, whole slices of Ali's cake is 12.

<u><em>Now, as it is the whole slices of Luke,kira and Ali are 6, 9 and 12.</em></u>

<u><em>Thus, it is possible.</em></u>

Therefore, the whole slices of Luke,kira and Ali are 6, 9 and 12. So it is possible.

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