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jeka57 [31]
4 years ago
9

Please help me with 5 with correct answer and try showing work if can

Mathematics
2 answers:
STALIN [3.7K]4 years ago
4 0
The answer would be A. -$16.25. It's negative because that's what Paul owes his dad. You add 10.75 and 5.50 and just turn it negative.
finlep [7]4 years ago
3 0
Its b $10.75+$5.50=$15.25 in debt
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Mr. Wang needs a total of 410 spoons for his son's birthday party. He currently has 278 spoonsIf has 12 spoons, what is the mini
Marina86 [1]

Answer:

Minimum amount of sets needed = 11 sets

Step-by-step explanation:

Total number of needed spoons = 410

Total number of available spoons = 278

Amount needed to be bought = 132 spoons

each set has 12 spoons

Therefore minimum amount of sets needed = 132/12 = 11 sets

6 0
4 years ago
Help please please show work
Nana76 [90]

Answer: 1267.18yd^2

Step-by-step explanation:

Formula: \pi r(r+\sqrt{h^2+r^2} )

We need;

\pi = 3.14\\r=?\\h=18yd

We don't have the radius, but we do have the diameter. A diameter is twice the radius. Therefore, we can divide the diameter by 2 in order to obtain the radius.

\frac{d}{2}= \frac{24}{2}=12yd

Now plug this info into the formula.

(3.14)(12yd)[(12yd)+\sqrt{(18yd)^2+(12yd)^2} ]

Let's solve the square root first.

(3.14)(12yd)[(12yd)+\sqrt{324yd^2+144yd^2} ]

(3.14)(12yd)[(12yd)+\sqrt{468yd^2} ]

(3.14)(12yd)[(12yd)+\sqrt{468yd^2} ]\\(3.14)(12yd)(12yd+21.63yd)

Now solve the sum

(3.14)(12yd)(33.63yd)\\

Multiply

1267.18yd^2

5 0
4 years ago
Select ALL of the trips that would take 4 hours to complete.
Annette [7]

Answer:

1, 4

Step-by-step explanation:

Hope this helps

6 0
3 years ago
Read 2 more answers
A garrison of 400men had food for 40days.After 10 days,200 more men joined them .How long will the food last now?(Assume that th
mestny [16]

Let x be the amount of food needed for one man for one day. At the beginning, we have enough food for 400 men for 40 days, i.e.

400\cdot 40\cdot x = 16000x

After 10 days, the 400 men will have consumed

400\cdot 10\cdot x = 4000x

food, impliying that the food remaining is

16000x-4000x=12000x

If 200 more men join the garrison, there are now 600 men. Each of them requires x food each day, and there are 12000x units of food remaining. They will last

\dfrac{12000x}{600}=20 days.

6 0
4 years ago
Please help me with this!!
zubka84 [21]

Step-by-step explanation:

84+36=120ans..........

3 0
3 years ago
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