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posledela
4 years ago
6

What did emest Rutherford’s gold foil experiment demonstrate about atoms

Chemistry
1 answer:
nekit [7.7K]4 years ago
7 0

The alpha particles that were fired at the gold foil were positively charged. ... These experiments led Rutherford to describe the atom as containing mostly empty space, with a very small, dense, positively charged nucleus at the center, which contained most of the mass of the atom, with the electrons orbiting the nucleus.

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The neighborhood swimming pool is 20 feet long, 8 feet wide, and 4 feet deep. Which formula below should be used to find how muc
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3 years ago
Identify the following as a compound or a mixture: quartz (SiO2)
Bumek [7]
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Nuclear reactions are different from chemical reactions, because in nuclear reactions, the transformations between species don't
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Electronic transitions (i.e., absorption of uv or visible light) of the conjugated molecule butadiene can be approximated using
dlinn [17]

Answer:

2.51 Angstroms

Explanation:

For a particle in a one dimensional box, the energy level, En, is given by the expression:

En = n²π² ħ² / 2ma²

where n is the energy level, ħ²  is Planck constant divided into 2π, m is the mass of the electron ( 9.1  x 10⁻³¹ Kg ), and a is the length of the one dimensional box.

We can calculate  the change in energy, ΔE, from n = 2 to n= 3  since we know the wavelength of the transition  ( ΔE = h c/λ ) and then substitute this value for the expresion of the ΔE for a particle in a box and solve for the  length a.

λ = 207 nm x 1 x 10⁻⁹ m/nm = 2.07 x 10⁻⁷ m      ( SI units )

ΔE = 6.626 x 10⁻³⁴ J·s x  3 x 10⁸ m/s  / 2.07 x 10⁻⁷ m

ΔE   = 9.60 x 10⁻¹⁹ J

ΔE(2⇒3) = ( 3 - 2 )  x  π² x ( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )

9.60 x 10⁻¹⁹ J  =  π² x( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )

⇒ a = 2.51 x 10⁻¹⁰ m

Converting to Angstroms:

a = 2.51 x 10⁻¹⁰ m x 1 x 10¹⁰ Angstrom / m = 2.51 Angstroms

6 0
4 years ago
How many moles of H2O are produced form 2.11 mole of oxygen?
aivan3 [116]

Answer:

4.22 mol H₂O

Explanation:

Step 1: Write the equation for the synthesis of water

2 H₂ + O₂ ⇒ 2 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to H₂O is 1:2.

Step 3: Calculate the moles of water produced from 2.11 moles of oxygen

We will use the previously established molar ratio.

2.11 mol O₂ × 2 mol H₂O/1 mol O₂ = 4.22 mol H₂O

4 0
3 years ago
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