A) Salt, because salt can easily dissolve in water. Oil would not dissolve or evaporate in water (think of an oil spill - does that oil dissappear?). Aluminum foil would definitely not dissolve in water, so it is not soluble.
we have a total of three times the original number (6.923 * 10**-7) moles of all ions, or 2.077 * 10**-6 moles of ions
<h3>What is aragonite-strontianite solid solution dissolution in nonstoichiometric Sr (HCO3)2 solutions?</h3>
Synthetic strontianite-aragonite solid-solution minerals were dissolved in non-stoichiometric CO2-saturated Sr(HCO3)2 and Ca(HCO3)2 solutions at 25°C. The reactions in Sr(HCO3)2 solutions frequently become incongruent, precipitating a Sr-rich phase before attaining stoichiometric saturation. Mechanical mixes of solids approach stoichiometric saturation in terms of the least stable solid in the combination.
This surficial phase has a thickness of 0-10 atomic layers in Sr(HCO3)2 solutions and a thickness of 0-4 layers in Ca(HCO3)2 solutions and dissolves and/or recrystallizes within 6 minutes of reaction.
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Answer:
Zero
Explanation:
Recall that;
E = q + w
Where;
q = heat, w = work done
When heat is absorbed by the system q is positive
When heat is evolved by the system q is negative
When the system does work, w is negative
When work is done on the system w is positive
Step 1
ΔE1= 60 KJ + 40 KJ = 100KJ
Step 2
ΔE2= (-30 KJ) + (-70 KJ) = (-100) KJ
ΔE1 + ΔE2= 100KJ + (-100) KJ = 0KJ
Answer: All organic compound depends on H-bonding with water. more stronger H-bonding with water more will be soluble.
Explanation:
1. It depends primarily upon the function groups of that compound. It also depends on the size of the compound.
2. some organic compound which soluble in water for example: alcohols, ethers, carboxylic acids. Because of the functional groups attached to the organic structure (the C-H backbone) are what effect the solubilities.Like carboxylic acids and alcohols form hydrogen bonds with the water, helping to solubilize it.
3. Take alcohols for example: methanol, ethanol, and isopropanol are all completely soluble in water. By the time you get to butanol and some of the larger alcohols, including those with more complex structures, they tend to be less soluble.
<u>Answer:</u> The equilibrium concentration of water is 0.597 M
<u>Explanation:</u>
Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
For a general chemical reaction:
The expression for 
is written as:
![K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
The concentration of pure solids and pure liquids are taken as 1 in the expression.
For the given chemical reaction:
The expression of 
for above equation is:
![K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2O%5D%5E2%7D%7B%5BH_2S%5D%5E2%5Ctimes%20%5BO_2%5D%7D)
We are given:
![[H_2S]_{eq}=0.671M](https://tex.z-dn.net/?f=%5BH_2S%5D_%7Beq%7D%3D0.671M)
![[O_2]_{eq}=0.587M](https://tex.z-dn.net/?f=%5BO_2%5D_%7Beq%7D%3D0.587M)
Putting values in above expression, we get:
![1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}](https://tex.z-dn.net/?f=1.35%3D%5Cfrac%7B%5BH_2O%5D%5E2%7D%7B%280.671%29%5E2%5Ctimes%200.587%7D)
![[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M](https://tex.z-dn.net/?f=%5BH_2O%5D%3D%5Csqrt%7B%281.35%5Ctimes%200.671%5Ctimes%200.671%5Ctimes%200.587%29%7D%3D0.597M)
Hence, the equilibrium concentration of water is 0.597 M
