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DedPeter [7]
3 years ago
8

What is the effect of molecular weight on melting and boiling point of alkanes??​

Chemistry
1 answer:
Readme [11.4K]3 years ago
8 0

Answer:

Their melting and boiling points of alkanes are relatively low. The higher the molecular weight (the greater the number of carbons), the higher the boiling point.

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Which of the following substances found in tobacco smoke stimulates the brain? A. acetone B. toluene C. nicotine D. ammonia Plea
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The answer is C. Nicotine is the substance found in tobacco smoke that stimulates the brain.

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What minimum energy is required to excite a vibration in HF?
Elodia [21]

Answer:

The energy of a vibrating molecule is quantized much like the energy of an electron in the hydrogen atom. The energy levels of a vibrating molecule are given by the equation: En=(n+21)hv where n is a quantum number with possible values of 1, 2, ... and v is the frequency of vibration.

Explanation:

hope it helps.

have a wonderful day!

7 0
2 years ago
When heat is applied to 80 grams of CaCO3, it yields 39 grams of B. Determine the percentage of the yield.
EleoNora [17]

The question is incomplete, the complete question is:

When heat is applied to 80 grams of CaCO3, it yields 39 grams of CaO Determine the percentage of the yield.

CaCO3→CaO + CO2

<u>Answer:</u> The % yield of the product is 87.05 %

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

We are given:

Given mass of CaCO_3 = 80 g

Molar mass of CaCO_3 = 100 g/mol

Putting values in equation 1, we get:

\text{Moles of }CaCO_3=\frac{80g}{100g/mol}=0.8mol

For the given chemical reaction:

CaCO_3\rightarrow CaO+CO_2

By stoichiometry of the reaction:

If 1 mole of CaCO_3 produces 1 mole of CaO

So, 0.8 moles of CaCO_3 will produce = \frac{1}{1}\times 0.8=0.8mol of CaO

We know, molar mass of CaO = 56 g/mol

Putting values in above equation, we get:

\text{Mass of CaO}=(0.8mol\times 56g/mol)=44.8g

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100 ......(2)

Given values:

Actual value of the product = 39 g

Theoretical value of the product = 44.8 g

Plugging values in equation 2:

\% \text{yield}=\frac{39 g}{44.8g}\times 100\\\\\% \text{yield}=87.05\%

Hence, the % yield of the product is 87.05 %

6 0
3 years ago
How many grams of water (H2O) are produced from 34 grams of oxygen (O2)? *
Dennis_Churaev [7]

Answer:

Explanation:

complete combustion reaction of  ethane is given by the reaction

2C2H6+7O2..............4CO2+6H2O

no of moles in 34 grams of O2=34/32=1.063

7mole of O2 produced 6 moles of H2O

therefore 1.063 moles of O2 produced=1.063*6/7=0.9 moles

now 0.9 moles of H2O contain how much grams=0.9*18=16.2 grams

3 0
3 years ago
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