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3 years ago

What is the effect of molecular weight on melting and boiling point of alkanes??

Chemistry

1 answer:

Readme [11.4K]3 years ago

8 0

Answer:

Their melting and boiling points of alkanes are relatively low. The higher the molecular weight (the greater the number of carbons), the higher the boiling point.

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Some fuel cells are powered by hydrogen. Scientists are looking into the decomposition of water (H2O) to make hydrogen fuel with

skad [1K]

A. Decomposing water requires a high activation energy.

Explanation:

In decomposing water to release hydrogen gas to make fuel cells, the process requires a very high activation energy.

2H₂O ⇆ 2H₂ + O₂

This is the overall reaction. O-H must be broken to release free hydrogen to produce hydrogen gas.

The O-H bond is a very strong force of attraction that requires a high activation energy to overcome.

The activation energy is the energy barrier that must be overcome before a reaction takes place.
The sun is a renewable source of energy.
Water decomposition produces useful oxygen gas needed by all life for cellular respiration.

Learn more:

Source of energy brainly.com/question/2948717

#learnwithBrainly

4 0

2 years ago

The graph below shows the volume and the mass of four different substances at STP.

sladkih [1.3K]

The formula of density is mass / volume

This means that
- high mass, low volume = high density
- high mass, high volume = so-so
- low mass, high volume = low density

From the graph shown,
D has the lowest density because it has low mass yet high volume.

6 0

3 years ago

A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate

Zarrin [17]

Answer: Empirical formula is $C_2H_5O$

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

Step 1 : Converting each of the given masses into their moles by dividing them by Molar masses.

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = $\frac{330g}{12g/mol}=27.5moles$

Moles of Hydrogen = $\frac{69.5g}{1g/mol}=69.5moles$

Moles of Oxygen = $\frac{220.2g}{16g/mol}=13.76moles$

Step 2: Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

$\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2$

$\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5$

$\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1$

Step 3: Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = $C_2H_5O$

7 0

2 years ago

Calculate the number of moles CuCl2 necessary to make 50 mL of a 0.15M solution

tekilochka [14]

Volume ⇒ 50 mL in liters : 50 / 1000 = 0.05 L

Molarity of solution ⇒ 0.15 M

Number of moles:

n = M * V

n = 0.15 * 0.05

n = 0.0075 moles of CuCl2

hope this helps!.

3 0

2 years ago

At 1000 K, Kp=19.9 for the reaction Fe2O3(s)+3CO(g)<--->2Fe(s)+3CO2(g) What are the equilibrium partial pressures of CO an

SOVA2 [1]

Answer: The equilibrium concentration of CO is 0.243 atm

Explanation:

We are given:

Initial partial pressure of carbon dioxide = 0.902 atm

As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.

For the given chemical equation:

$Fe_2O_3(s)+3CO(g)\rightleftharpoons 2Fe(s)+3CO_2(g)$