Yes their is a way go to your downloads see if you have some thing or their shall be something that you can type in your computer and find something or you can go to Youtube or google and they can show you a video or some articles.
It kind of depends on the intended language, but I can see the following mistakes:
- lines not terminated with a semicolon (but not all languages require this)
- while statement missing parenthesis, ie., while (num1 <= num2), also not required in all languages
- statements below the while statement must be grouped by curly braces
- num1+5 should be num1=num1+5 or num1 += 5
Output will be:
10
15
20
25
30
Answer:
because you are asking questions like this
Explanation:
when you ask questions you lose points
Control + P (push these buttons at the same time)
or right click and print.
if you are printing a webpage, the steps are the same.
if you are using Word, then you just need to find the File tab and print should be in the list.
Answer:
a. 2100
b. 2199
Explanation:
GIven that:
The file size = 1000 MB
The payload size is = 100 bytes
The negotiated window size is = 1000 bytes.
This implies that the sliding window can accommodate maximum number of 10 packets
The sender receives an ACK 1200 from the receiver.
Total byte of the file is :
1000 MB = 1024000000 bytes
a.
Sender receives an ACK 1200 from the receiver but still two packets are still unacknowledged
=1200 + 9 * 100
= 1200 + 900
= 2100
b. What is the last byte number that can be sent without an ACK being sent by the receiver?
b. Usually byte number starts from zero, in the first packet, the last byte will be 99 because it is in 1000th place.
Thus; the last byte number send is :
= 1200 + 10 *100 -1
= 1200 + 1000-1
= 1200 + 999
= 2199