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VikaD [51]
3 years ago
14

The readline method reads text until an end of line symbol is encountered, how is an end of line character represented

Computers and Technology
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer:

\n

Explanation:

readline() method is used to read one line from a file. It returns that line from the file.    

This line from the file is returned as a string. This string contains a \n at the end which is called a new line character.

So the readline method reads text until an end of line symbol is encountered, and this end of line character is represented by \n.

For example if the file "abc.txt" contains the lines:

Welcome to abc file.

This file is for demonstrating how read line works.

Consider the following code:

f = open("abc.txt", "r")  #opens the file in read mode

print(f.readline()) # read one line from file and displays it

The output is:

Welcome to abc file.    

The readline() method reads one line and the print method displays that line.                        

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What is the post condition of an expression or variable
Jet001 [13]

Answer:

The post condition is simply a statement expressing what work has been accomplished by the function. This work might involve reading or writing data, changing the values of variable parameters, or other actions.

8 0
4 years ago
A home user reports to a network technician that the Internet is slow. The network administrator discovers that multiple unknown
BabaBlast [244]

Answer:

Option (A) A successful WPS attack has occurred

Explanation:

  • WPS stands for Wi-Fi Protected Setup.
  • Its a network security protocol in the Wi-Fi which has a vulnerability.
  • The connection to the Wi-Fi can be established through the router in four ways. They are
  • (a) PIN method
  • (b) Push button method
  • (c) Near field communication method
  • (d) USB Method.
  • Out of all the modes to be connected to the network, the PIN method has a flaw in it.
  • In this PIN method, an attacker can brute force the PIN (guessing the PIN by some techniques) and gain unauthorized access to the network.
  • In the given case in the question, the network administrator finds that multiple unauthorized devices has gained access to the network.
  • Option (A) is correct.
  • Option (B) ARP Poisoning, (C) botnet and (D) Evil Twin attack are different and so are the wrong options.  
3 0
3 years ago
Read 2 more answers
It takes 2 seconds to read or write one block from/to disk and it also takes 1 second of CPU time to merge one block of records.
Alexxx [7]

Answer:

Part a: For optimal 4-way merging, initiate with one dummy run of size 0 and merge this with the 3 smallest runs. Than merge the result to the remaining 3 runs to get a merged run of length 6000 records.

Part b: The optimal 4-way  merging takes about 249 seconds.

Explanation:

The complete question is missing while searching for the question online, a similar question is found which is solved as below:

Part a

<em>For optimal 4-way merging, we need one dummy run with size 0.</em>

  1. Merge 4 runs with size 0, 500, 800, and 1000 to produce a run with a run length of 2300. The new run length is calculated as follows L_{mrg}=L_0+L_1+L_2+L_3=0+500+800+1000=2300
  2. Merge the run as made in step 1 with the remaining 3 runs bearing length 1000, 1200, 1500. The merged run length is 6000 and is calculated as follows

       L_{merged}=L_{mrg}+L_4+L_5+L_6=2300+1000+1200+1500=6000

<em>The resulting run has length 6000 records</em>.

Part b

<u><em>For step 1</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{2300}{100} \times 2 sec\\T_{I.O}=46 sec

So the input/output time is 46 seconds for step 01.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 2300 for step 01
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{2300}{100} \times 1 sec\\T_{CPU}=23 sec

So the CPU  time is 23 seconds for step 01.

Total time in step 01

T_{step-01}=T_{I.O}+T_{CPU}\\T_{step-01}=46+23\\T_{step-01}=69 sec\\

Total time in step 01 is 69 seconds.

<u><em>For step 2</em></u>

Input Output Time

Input Output Time is given as

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{I/O per block} is 2 sec

So

T_{I.O}=\frac{L_{run}}{Size_{block}} \times Time_{I/O \, per\,  block}\\T_{I.O}=\frac{6000}{100} \times 2 sec\\T_{I.O}=120 sec

So the input/output time is 120 seconds for step 02.

CPU  Time

CPU Time is given as

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}

Here

  • L_run is 6000 for step 02
  • Size_block is 100 as given
  • Time_{CPU per block} is 1 sec

So

T_{CPU}=\frac{L_{run}}{Size_{block}} \times Time_{CPU \, per\,  block}\\T_{CPU}=\frac{6000}{100} \times 1 sec\\T_{CPU}=60 sec

So the CPU  time is 60 seconds for step 02.

Total time in step 02

T_{step-02}=T_{I.O}+T_{CPU}\\T_{step-02}=120+60\\T_{step-02}=180 sec\\

Total time in step 02 is 180 seconds

Merging Time (Total)

<em>Now  the total time for merging is given as </em>

T_{merge}=T_{step-01}+T_{step-02}\\T_{merge}=69+180\\T_{merge}=249 sec\\

Total time in merging is 249 seconds seconds

5 0
3 years ago
Imma say something random...
Fynjy0 [20]

Answer:

Uh I don't understand what you said.

Explanation:

N/A

5 0
3 years ago
Read 2 more answers
If you’re presenting in a darkened room, what text and background should you use to provide maximum readability?1) Light text on
ludmilkaskok [199]

Answer:

1

Explanation:

1 because it would be difficult for people to read on the other ones that you put.

3 0
3 years ago
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