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Agata [3.3K]
3 years ago
12

HELP WILL BRAINLY I F HELP FAST I HAVE A LOT

Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0
The answer is c.its written that their can be multiple answers or single
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The graph of y = -5x + 1
Colt1911 [192]

y = -5x + 1

[y = mx + b     "m" is the slope, "b" is the y-intercept (the y value when x = 0)]

So your slope is -5, and your y-intercept is 1 or (0,1)


Slope = \frac{rise}{run}

Rise is the number of units you go up(+) or down(-).

Run is the number of units you go to the right.


Since your slope is -5 or \frac{-5}{1}, you go down 5 units, and to the right 1 unit.

6 0
3 years ago
State the horizontal asymptote of the rational function.<br> f(x) = x^2 + 9x-9/x-9
dusya [7]

Answer:

no horizontal asymptote

5 0
3 years ago
In 2010 the population of alaska was about 710200 what is this number written in word form
Svetradugi [14.3K]
Seven hundred and ten thousand two hundred
7 0
2 years ago
The vertices of a right triangle are (0, 0), (1, 0), and (0, 1).
Alchen [17]

Answer:

(3,3)

Step-by-step explanation:

Given

Vertices: (0,0)\ (1,0)\ (0,1)

Scale\ Factor = 3

Required

Determine which can't be any of the new vertices

First, we need to determine the new vertices:

New\ Vertex = Scale\ Factor * Old\ Vertex

For (0,0):

New\ Vertex = 3 * (0,0)

New\ Vertex = (3 * 0,3 * 0)

New\ Vertex = (0,0)

For (1,0):

New\ Vertex = 3 * (1,0)

New\ Vertex =  (3 * 1,3 * 0)

New\ Vertex =  (3,0)

For (0,1):

New\ Vertex =  3 * (0,1)

New\ Vertex =  (3 * 0,3 * 1)

New\ Vertex =  (0,3)

<em>Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle</em>

<em></em>

5 0
3 years ago
5-12 please it’s due in half an hour
Ber [7]
The answer to number 5 is 128
8 0
2 years ago
Read 2 more answers
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