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bezimeni [28]
4 years ago
15

Whats 0 divide 0 i really want to know

Mathematics
1 answer:
Gelneren [198K]4 years ago
4 0

Answer

N/A

Step-by-step explanation:

lets take a step into our imaginations, ok?

So when you divide, you're basically splitting the numerator into as many parts as the denominator.

imagine you have a chocolate bar, and it has 6 pieces and you want to split it evenly between your 3 friends.

you split it into three equal parts to get 2 pieces per person.

When you divide 0 by 0, your splitting 0 chocolate bars into 0 equal portions, which is why this problem isn't solvable.

You might be interested in
If g (x) = 3x²-4, then find g (-3)
Semenov [28]

Answer:

g(-3) = 23

Step-by-step explanation:

This question is telling us that x = -3. Knowing this, we can plug x into the equation and solve to find g(-3).

g(-3) = 3(-3)^{2} -4

g(-3) =3(9)-4                      Square -3 to get 9

g(-3) = 27-4                         Multiply 9 by 3 to get 27

g(-3) = 23                               Subtract 4 from 27 to get 23

Thus, g(-3) is equal to 23.

I hope this helps! Good luck!

6 0
2 years ago
Can anyone teach plsssss........................ Given that PR= 17cm and SR= 6cm.Find the length, in cm of TS. ​
Lemur [1.5K]

Answer:

9cm

Step-by-step explanation:

  1. Since PQST is a rectangle, ∠QST=∠QSR=∠90º. So triangle QSR is a right triangle.
  2. By the Pythagorean Theorem and that SR=6 and QR=10, we can say that 6^2+b^2=10^2. So, 36+b^2=100. And b^2=64 and b=8. So QS=8.
  3. Now we know that QS=PT=8.
  4. By the Pythagorean Theorem and that PR=17 and PT=8, we can say a^2+8^2=17^2. So, a^2+64=289. And a^2=225 and a=15.
  5. We know that TR=15 and SR=6 and TR-SR=TS, so 15-6=9.
8 0
3 years ago
A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish
Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or \frac{x}{y}=\frac{333}{444}

⇒ \frac{x}{y}=\frac{3}{4}

⇒ y = \frac{4x}{3} --------(1)

Similarly x' : y' = 333 : 444

⇒ \frac{x'}{y'}=\frac{333}{444}

⇒ \frac{x'}{y'}=\frac{3}{4}

⇒ x' = \frac{3y'}{4} ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

\frac{x+y}{x'+y'}=\frac{464646}{555}

Now we replace the values of x and y' from equation (1) and equation (2)

\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}

\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}

\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}

\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}

\frac{x}{y'}=\frac{232323}{370}

\frac{y'}{x}=\frac{370}{232323}

\frac{y'}{x}=\frac{10}{6279}

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0
4 years ago
3y^4+9y^3-120y^2=0 Need Answer ASAP
Shkiper50 [21]

Answer:

y  =  0 ,  5 ,  − 8

(* ̄3 ̄)╭

7 0
3 years ago
Read 2 more answers
Suppose that the waiting time for a license plate renewal at a local office of a state motor vehicle department has been found t
Wittaler [7]

Answer:

a=30 +1.04*8=38.32

So the value of height that separates the bottom 85% of data from the top 15% is 38.32.  

C) 38.32

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the waiting time in minutes of a population, and for this case we know the distribution for X is given by:

X \sim N(30,8)  

Where \mu=30 and \sigma=8

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

We want to find a value a, such that we satisfy this condition:

P(X>a)=0.15   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.85 of the area on the left and 0.15 of the area on the right it's z=1.04. On this case P(Z<1.04)=0.85 and P(z>1.04)=0.15

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.04

And if we solve for a we got

a=30 +1.04*8=38.32

So the value of height that separates the bottom 85% of data from the top 15% is 38.32.  

C) 38.32

7 0
4 years ago
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