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zvonat [6]
3 years ago
10

Danny invests $10,000 in a savings account that pays 3.5% simple interest. If Danny does not make any additional deposits or wit

hdrawals, how much will be in the account after 7 years?
Mathematics
2 answers:
SashulF [63]3 years ago
5 0

Answer:

Danny will have 12,450 in his savings account

Step-by-step explanation:

P is the principal amount, $10000.00.

r is the interest rate, 3.5% per year, or in decimal form, 3.5/100=0.035.

t is the time involved, 7....year(s) time periods.

So, t is 7....year time periods.

To find the simple interest, we multiply 10000 × 0.035 × 7 to get that:

The interest is: $2450.00

10000.00 + 2450.00 = 12450.00.

oksian1 [2.3K]3 years ago
5 0

Answer:

He will have 12,450.00

Step-by-step explanation:

Ok if he has the starting amount at 10,000 thats your initial value. So to get your solution you have A=10,000 x .035t.

A=10,000 x 0.35 doing that you get 350, being the amount put into the account each year.

Next you do 10000+350(7) giving you 12450.

Hope this helps

You might be interested in
What is meant by the term financial planning?
guajiro [1.7K]

Answer:

<h2>a. Long-term goals are reached over an extended period of time, so your current income does not affect them.</h2>

Financial Planning is determining how you're going to handle your money.  Usually after seeking out it's competition, a company will create goals to ensure that money continues to flows through smoothly after their objectives are set.

<em>I hope this helped you!</em>

5 0
3 years ago
Could someone help with the questions in the images below? I found them difficult
zubka84 [21]
Question 1a - You have got this correct, the median mark is 35
Question 1b- To work out the range, you must do the largest value subtract the smallest value. For your data, this would be 57 - 13 = 44

Question 2 - You have drawn the lines in the correct places, but you have not used a ruler. In order to get full marks on a question like this you must use a ruler.

Question 3 - Your lower quartile and median is correct, to find the upper quartile, we do 3(n/4). 'n' is the number of data points - in this case 120.
120/4 = 30
30 x 3 = 90
Go across the graph at 90 to see when the line is hit.
From what I can tell, the Upper Quartile is 3.

Next just find the maximum value.
Again, by the looks of it, the Maximum value is 8.5.

Now you have all the data needed for the box plot.

Min = 0
LQ = 0.8
Med = 2.1
UQ =  3
Max = 8.5

Using this information, draw a box plot like you did on the previous question.
<em>Again, I must stress that any line that you draw (unless purposely curved) must be drawn with a ruler; even on the graph at the top, during you working out. If you do not use a ruler, marks can be lost/taken away.</em>

Question 4a - For the median on a cumulative frequency chart, you must find the halfway point in the data. For this, we do n/2. In this case, n = 40
40/2 = 20
Draw a line (using  ruler) across at 20 until you reach the line.
Draw another one down to help you read the number.
The median looks like 34 seconds.
Question 4b - For this question, we already know the Min, Med and Max. Now we must work out the LQ and UQ.

Remember, LQ = n/4
In this case, n = 40
40/4 = 10
Look across at ten and you will find that the LQ = 16 seconds

To work out the UQ, we multiply the LQ place by 3 3(n/4).
3 x 10 = 30
30 on the graph takes us up to 45 seconds.

We now know that the:
Min = 9
LQ = 16
Med = 34
UQ = 45
Max = 57

With this information, draw a box plot like you have in the previous questions.

Question 5 - Good things to always compare on box plots are the Min/Max/Range and the Inter Quartile Range.
The boys had a lowest minimum and a higher maximum, this means that their range is larger, resulting in a large spread of data in comparison to the girls.
The Inter Quartile Range is the difference between the Upper Quartile and the Lower Quartile (how wide the box is).
The boy IQR = 45 - 16 = 29
The girls IQR = 34 - 23 = 11
Again, the girls have much more concise results; even though they did not get the quickest result, they were more like one another.

Question 5a - The median in a box plot is always the line down the centre of the box. In this case:
Median = 24 marks
Question 5b - The IQR is always the UQ - LQ
With this data, the IQR is the following:
36 - 17 = 19 marks

Hope this helps
6 0
3 years ago
In triangle ABC, what is the measure of angle C?
agasfer [191]
Depends on the angle of A and B
8 0
3 years ago
g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20
Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

X\sim N(\mu = 50, \sigma =6)

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0
3 years ago
4(2x + 2) + 12 &gt; 100
Komok [63]

Answer:

x > 10

Step-by-step explanation:

4(2x + 2) + 12 > 100

4(2x + 2) > 100 -12

4(2x + 2) > 88

2x + 2 > 22

2x> 22-2

2x > 20

x > 10

3 0
3 years ago
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