Answer:
cuteboy979409
Step-by-step explanation:
I am sorry mam a was not able to answer this question.
Answer:
Those areas are: A 1 = 12, A 2 = 19
Step-by-step explanation:
The area of shape 1 : it consists of 1 square + 4 right triangles
Area of the square: A = a², area of the triangle: A = 1/2 · a · h
A 1 = 2² + 4 · 1/2 · 2 · 2 = 4 + 8 = 12
The area of shape 2 : it consists of 2 isosceles triangles
A 2 = 1/2 · 2 · 4 + 1/2 · 6 · 5 = 4 + 15 = 19
4) In triangle, angle opposite to perpendicular is 90-60 = 30
So, tan Ф = P/B
tan 30 = a / 6
1/√3 = a/6
a = 6/√3
a = 2√3
Now, cosФ = B/H
cos 30 = 6/b
√3/2 = 6/b
b = 6*2/√3
b = 12/√3
b = 4√3
In short, Your Answer would be a = 2√3 and b = 4√3
Hope this helps!
Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.
