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Leni [432]
2 years ago
10

Given a sample of 35, what is the sample standard deviation of a pair of jeans if the 90% confidence interval is [37.14, 42.86]

Mathematics
1 answer:
DENIUS [597]2 years ago
7 0

Answer:

<h2>10.295</h2>

Step-by-step explanation:

Using the value for calculating the confidence interval as given;

CI = xbar + Z*σ/√n

xbar  is the mean = 37.14+42.86/2

xbar= 80/2

xbar = 40

Z is the z-score at the 90% confidence = 1.645

σ is the standard deviation

n is the sample size = 35

Given the confidence interval CI as [37.14, 42.86]

Using  the maximum value of the confidence interval to get the value of the standard deviation, we will have;

42.86 =  xbar + Z*σ/√n

42.86 = 40 + 1.645* σ/√35

42.86-40 = 1.645*σ/√35

2.86 = 1.645*σ/√35

2.86/1.645 = σ/√35

1.739 = σ/√35

1.739 = σ/5.92

σ= 1.739*5.92

σ = 10.295

Hence, the sample standard deviation of a pair of jeans is 10.295

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The side length of the base of a square pyramid is 30 centimeters. The height of the pyramid is 45 centimeters.
puteri [66]

Answer:

volume = 13500 cm^{3}

Step-by-step explanation:

For a given pyramid, its volume can be determined by:

volume of pyramid = \frac{lwh}{3}

Where: l is the base length, w is the base width and h id the height of the pyramid.

For the given question, l 30 cm, w = 30 cm and h = 45 cm.

So that,

volume = \frac{30*30*45}{3}

            = \frac{40500}{3}

            = 13500

volume = 13500 cm^{3}

The volume of the pyramid is 13500 cm^{3}.

6 0
2 years ago
Assuming that boy and girl babies are equally likely, what would be Kathy's probability of having at most one daughter if she
JulijaS [17]

Answer: 0.3125.

Step-by-step explanation:

  • The chance of having a boy is 0.5,
  • the chance of having a girl is also 0.5.

<u>Outcome 1: all boys</u>

boy  boy  boy  boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

<u>Outcome 2: first child is a girl, all others are boys</u>

girl   boy   boy   boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

<u>Outcome 3: second child is a girl, all others are boys</u>

boy   girl   boy   boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

<u>Outcome 4: third child is a girl, all others are boys</u>

boy   boy   girl   boy

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

<u>Outcome 5: fourth child is a girl, all others are boys</u>

boy   boy   boy   girl

0.5 * 0.5 * 0.5 * 0.5 = 0.0625

Therefore,

0.0625 + 0.0625 + 0.0625 + 0.0625 + 0.0625 = 0.0625 * 5 = 0.3125

4 0
1 year ago
Natalia begins to find the mean absolute deviation of this data set. She finds the mean of the data and then finds the distance
s2008m [1.1K]
Hello!

To calculate mean absolute deviation, you find the mean, find the distance between each data point and the mean, add up those distances, and divide by the number of data points.

In this scenario, after Natalia finds the distances, she must add them all up and then divide by the number of data points.

I hope this helps!
3 0
3 years ago
Read 2 more answers
5a+4b=65 elimination substitute and check
SIZIF [17.4K]

Answer:

a=13 - 4b/5

b=65/4-5a/4

Step-by-step explanation:

4 0
2 years ago
Suppose that the probability that a person will develop hypertension over a life time is 60%. Of 13 graduating students from the
Savatey [412]

Answer:

The mean number of the students who develop hypertension over a life time is 7.8.

Step-by-step explanation:

For each person, there are only two possible outcomes, either they will develop hypertension, or they will not. The probability of a person developing hypertension is independent of any other person, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

Suppose that the probability that a person will develop hypertension over a life time is 60%.

This means that p = 0.6

13 graduating students from the same college are selected at random.

This means that n = 13

Find the mean number of the students who develop hypertension over a life time

E(X) = np = 13*0.6 = 7.8

The mean number of the students who develop hypertension over a life time is 7.8.

5 0
2 years ago
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