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almond37 [142]
3 years ago
5

In a college parking lot, the number of ordinary cars is larger than the number of sport utility vehicles by 42.9%. the differen

ce between the number of cars and the number of suvs is 12. find the number of suvs in the lot.
Mathematics
1 answer:
fenix001 [56]3 years ago
6 0
Let
 x = number of common cars
 y = number of suvs
 we can write the following system of equations
 x-y = 12
 x = 1.429y
 Solving the system we have
 x-y = 12
 1.429y-y = 12
 and (1,429-1) = 12
 y = (12) / (1,429-1) = 27.97202797
 then,
 x = 1429 * (27.97202797)
 x = 39.97202797
 answer
 The number of suvs in the parking lot is 28
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Explanation:

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However, we don't know the value of w, so we undo each step of PEMDAS going backwards.

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Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.
irina1246 [14]
Lagrange multipliers:

L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)

L_x=y^2z^2+\lambda=0
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We also need to check the boundary of the region, i.e. the intersection of x+y+z=5 with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force f(x,y,z)=0, so the point we found is the only extremum.
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4 years ago
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Answer:

9) C. 35 + 0.12x = 44.36

10) B

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9)

44.36 is the TOTAL so the equations have to EQUAL it.

PER mile means it's a variable so it's 0.12x:

35 is a constant so there's no variable attached:

35 + 0.12x = 44.36

10)

B because you have to cancel the y values and to do that, you multiply the 1st equation by 3.

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Kindly check explanation

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