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zzz [600]
3 years ago
13

Subtracting rational expressions: 6 - x+5/(7x-5)(x+4) Please show work

Mathematics
1 answer:
velikii [3]3 years ago
5 0
<h3>Answer:</h3>

\dfrac{42x^2+137x-125}{7x^2+23x-20}

<h3>Explanation:</h3>

You know that the sum of a number and a fraction is ...

... a + b/c = (ac +b)/c

Here, you have ...

... a = 6

... b = -(x+5)

... c = (7x-5)(x+4) = 7x² +23x -20

Then ...

... (ac +b)/c = (6(7x² +23x -20) -(x +5))/(7x² +23x -20)

... = (42x² +138x -120 -x -5)/(7x² +23x -20)

... = (42x² +137x -125)/(7x² +23x -20)

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Step-by-step explanation:

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3 years ago
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Answer:

c = 4/3

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Since we have paranthesis, first use the dsitributive property [multiply 3 by c and 8]

3(c + 8) = 28

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