Subtracting rational expressions: 6 - x+5/(7x-5)(x+4) Please show work
1 answer:
<h3>Answer:</h3>
You know that the sum of a number and a fraction is ...
... a + b/c = (ac +b)/c
Here, you have ...
... a = 6
... b = -(x+5)
... c = (7x-5)(x+4) = 7x² +23x -20
Then ...
... (ac +b)/c = (6(7x² +23x -20) -(x +5))/(7x² +23x -20)
... = (42x² +138x -120 -x -5)/(7x² +23x -20)
... = (42x² +137x -125)/(7x² +23x -20)
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