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Ipatiy [6.2K]
3 years ago
13

Help me please, thanks. -Tornado

Mathematics
2 answers:
Ann [662]3 years ago
6 0

Answer:

x =   -  \frac{25}{3}

Step-by-step explanation:

\frac{10}{3}  =  \frac{x}{( -  \frac{5}{2}) }

<h3>i) simplify the complex fraction</h3>

\frac{10}{3}  =  -  \frac{2x}{5}

<h3>ii) simplify the equation using cross multiplication</h3>

5(10) =  - 2x(3)

50 =  - 6x

<h3>iii) swap the sides of the equation</h3>

- 6x = 50

<h3>iv) divide both sides of the equation by -6</h3>

\frac{ - 6x}{ - 6}  =  \frac{50}{ - 6}

x =  -  \frac{50}{6}

<h3>v) simplify the fraction</h3>

x =  -  \frac{25}{3}

jok3333 [9.3K]3 years ago
4 0
Yes that answers correct like this please
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HELP!!!!! I AM DESPERATE!!!!!
vfiekz [6]

Answer:

1. Linear

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4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=6%5Csqrt%7B3%7D%2B2%281-%5Csqrt%7B27%7D%29%3D2" id="TexFormula1" title="6\sqrt{3}+2(1-\sqrt{27
skelet666 [1.2K]

Answer:

This is true.

Step-by-step explanation:

Step 1: see that √27 is the same as √3*3*3 and thus 3√3

Step 2: remove parenthesis so that 2(1-3√3) becomes 2 - 6√3

Step 3: observe that the equation now becomes 6√3 + 2 - 6√3 = 2

if you simplify any further, you are left with 0=0, which is true.

Comment if there is any step that requires more details...

3 0
3 years ago
Read 2 more answers
Please help me. 20 POINTS​
Serhud [2]

Answer:

No. Angle 1 is an obtuse angle while angle 2 is an acute angle. obtuse angles are more than 90 degrees, which is more than an acute angle's less than 90 degrees.

Step-by-step explanation:

7 0
3 years ago
Help please...I don't get this (40 points and I'll give brainliest)
dexar [7]

A x = 0

using the law of exponents a^{0} = 1

for (6² )^ x = 1 then x = 0

B note that 6^{0} = 1 ⇒ x = 1

2 → 2^8 × 3^(-5) × 1^(-2) × 3^(-8) × 2^(-12) × 2^(28)

= 2^(8 -12 + 28) × 1 × 3^(- 5 - 8)

= 2^24 × 3^(- 13) = 2^(24)/3^(13) = 10.523 ( 3 dec. places)




6 0
3 years ago
This is due at 11:59 and urgent please answer this, tyyy :))
serious [3.7K]

Answer:

(0,-5). y=mx+b or -5=0 × 0+b, or solving for b: b=-5-(0)(0). b=-5.

(2,-5). y=mx+b or -5=0 × 2+b, or solving for b: b=-5-(0)(2). b=-5.

y=-5

8 0
3 years ago
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