The answer is A = P²/16
The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s = s²
Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.
Step 1:
P = 4s
s = P/4
Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16
Answer:
34.6 units
Step-by-step explanation:
The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.
The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).
Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:
Distance between point A(-6, 2) and point B(2, 6):

Let,





(nearest tenth)
Distance between B(2, 6) and C(7, 1):

Let,





(nearest tenth)
Distance between C(7, 1) and D(3, -5):

Let,





(nearest tenth)
Distance between D(3, -5) and A(-6, 2):

Let,





(nearest tenth)
Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units
Step-by-step explanation:
Given that:-
So, we can concert 15 minutes to hours.
So,
60 minutes = 1 hour
1 minute = 1/60
15 minutes =

Okay, now we will apply first for 0.4 hours.





Now, second one:-



Hope it helps :D
<span>1st train DATA:
rate = 50 mph ; time = x hrs ; distance = rt = 50x miles
2nd train DATA:
rate = 55 mph ; time = (x-(1/2)) hrs ; distance = rt = 55(x-(1/2)) miles
Equation:
distance = distance
50x = 55(x-(1/2)
50x = 55x - (55/2)
-5x = -55/2
x = 11/2
x = 5 1/2 hrs (time at which the 2nd train overtakes the 1st train)
Hope this helps!</span>
I do believe it’s 250$
**The first choice:**
Principal: 5,000$
Rate(%): 5
Time(year): 3 years
A: 5,750$
**Second choice**
Principal: 5,000$
Rate(%): 4%
Time(year): 5 years
A: 6,000$
6,000-5,750=250$
Hope this helps!