How do I do this problem

Write the area A of a square as a function of its perimeter P. ...?

Svetradugi [14.3K]

The answer is A = P²/16

The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s = s²

Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.

Step 1:
P = 4s
s = P/4

Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16

4 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

2 years ago

The cells of a bacteria doubles in every 15 minutes. A scientist begins with a single cell. How many cells will be there after (

Anastaziya [24]

Step-by-step explanation:

Given that:-

1 cell = 15 minutes

So, we can concert 15 minutes to hours.

So,

60 minutes = 1 hour

1 minute = 1/60

15 minutes =

$\frac{15}{60} = 0.25 \: hrs$

Okay, now we will apply first for 0.4 hours.

$0.25 \: hrs= 1 \: cell$

$1 \: hr = \frac{1}{0.25}$

$0.4 \: hrs = \frac{0.4}{0.25}$

$= 1.6 \: cells$

$= 16 \times {10}^{ - 1} \: cells$

Now, second one:-

$10 \: hrs = \frac{10}{0.25}$

$= 40 \: cells$

$= 0.4 \times {10}^{2} \: cells$

Hope it helps :D

6 0

2 years ago

A train traveling 50 mph left a station 30 minutes before a second train running at 55 mph. how soon did the second train overta

Finger [1]

<span>1st train DATA:
rate = 50 mph ; time = x hrs ; distance = rt = 50x miles

2nd train DATA:
rate = 55 mph ; time = (x-(1/2)) hrs ; distance = rt = 55(x-(1/2)) miles

Equation:
distance = distance
50x = 55(x-(1/2)
50x = 55x - (55/2)
-5x = -55/2
x = 11/2
x = 5 1/2 hrs (time at which the 2nd train overtakes the 1st train)
Hope this helps!</span>

8 0

2 years ago

Read 2 more answers

Steven is taking out a loan in the amount of $5,000. His choices are a 3-year loan at 5% simple interest and a 5 -year loan at 4

Andre45 [30]

I do believe it’s 250$

**The first choice:**
Principal: 5,000$
Rate(%): 5
Time(year): 3 years
A: 5,750$

**Second choice**
Principal: 5,000$
Rate(%): 4%
Time(year): 5 years
A: 6,000$

6,000-5,750=250$

Hope this helps!

8 0

3 years ago