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ch4aika [34]
3 years ago
10

Perpendicular lines intersect to form right angles. Always, sometimes, never

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
5 0

Answer:

The answer is always

Step-by-step explanation:

adelina 88 [10]3 years ago
3 0

Answer:

Your answer is ALWAYS!!!

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Please help
Ira Lisetskai [31]

Answer:

285°

Step-by-step explanation:

105+180=285

7 0
2 years ago
Find the centroid for an area defined by the equations y = x² + 3 and y = - (x – 2)² + 7
meriva
The points where the 2 graphs intersect is  where x = 0 and x = 2.

-                 2                                  2
x   =    INT               x dA     /    INT        dA
                  0                                  0

INT dA   = INT -x^2 + 4x + 3 - (x^2 + 3 ) dx  =      INT -2x^2  + 4x
               =   -2 x^3/3 + 2x^2
               =   2.667  between 0 and 2

xdA  =   -2x^3 + 4x^2  INT xdA  =   -x^4/2 + 4x^3/3 = 2.667

centroid = 2.667 / 2.667  = 1  (x = 1)
3 0
3 years ago
Read 2 more answers
EXPERT HELP: DON'T GUESS and SHOW YOU WORK
Tamiku [17]

Answer:

3

Step-by-step explanation:

the mean is 103, as a result you must find the distance.

from 100 to 103 is 3

from 194 to 103 is 1

from 107 to 103 is 4

Then find the mean again youll get 18/6 which is 3

3 0
2 years ago
Read 2 more answers
16- X = -2<br> Solve for x
Licemer1 [7]

Answer: x=18

Step-by-step explanation: 16-18=-2

Good luck! :)

7 0
3 years ago
Read 2 more answers
4.) Which best describes the relationship between &lt; AFB and &lt; AFD?
MAVERICK [17]

Answer:

C. Supplementary angles

Step-by-step explanation:

Given

<AFB = 72

Required

Relationship of <AFB and <AFD

<AFB and <AFD are on a straight line and angle on a straight line is 180

From the presentation of both angles,

<AFB + <AFD = 180

Substitute 72 for <AFB

72 + <AFD = 180

Make <AFB the subject of formula

<AFD = 180 - 72

<AFD = 108

Since both <AFB and <AFD sums to 180, then they are supplementary angles.

Hence, the relationship between both angles is supplementary angles

5 0
3 years ago
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