Answer:
8
Step-by-step explanation:
1,2,3,4,6,8,12,24
Step-by-step explanation:
f(x) = x² + x + 3/4
in general, such a quadratic function is defined as
f(x) = a×x² + b×x + c
the solution for finding the values of x where a quadratic function value is 0 (there are as many solutions as the highest exponent of x, so 2 here in our case)
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = 1
c = 3/4
x = (-1 ± sqrt(1² - 4×1×3/4))/(2×1) =
= (-1 ± sqrt(1 - 3))/2 = (-1 ± sqrt(-2))/2 =
= (-1 ± sqrt(2)i)/2
x1 = (-1 + sqrt(2)i) / 2
x2 = (-1 - sqrt(2)i) / 2
remember, i = sqrt(-1)
f(x) has no 0 results for x = real numbers.
for the solution we need to use imaginary numbers.
Answer:
(-2, 4)
Step-by-step explanation:
~When reflecting a point of the x-axis, the x value (or first number inside the parenthesis) does not change.
The reason the x-value does not change is because you are reflecting over the x-axis, making the point go up or down. That will change the y-value but the x-value only changes if you move to the left or the right. In this case, you can see that the point's x-value is -2, so that will not change. It's current y-value however is -4. When reflecting over an axis, the number that is changing (in this case the y-value) will just be flipped from positive to negative, or vise versa. In this case, -4 will be reflected to be 4, making point C reflected over the x-axis (-2, 4).
Answer:
<h2>
∠PZQ = 63°</h2>
Step-by-step explanation:
If point P is the interior of ∠OZQ , then the mathematical operation is true;
∠OZP + ∠PZQ = ∠OZQ
Given parameters
∠OZQ = 125°
∠OZP = 62°
Required
∠PZQ
TO get ∠PZQ, we will substitute the given parameters into the expression above as shown
∠OZP + ∠PZQ = ∠OZQ
62° + ∠PZQ = 125°
subtract 62° from both sides
62° + ∠PZQ - 62° = 125° - 62°
∠PZQ = 125° - 62°
∠PZQ = 63°
<em>Hence the value of ∠PZQ is 63°</em>
Answer:
28 members up in that club have voted.
