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KiRa [710]
3 years ago
8

Bryan made up a game. Each team starts with seven points. Each time a team answers a question correctly, they earn five points.

The equation used to find the total number of points is 7 + (5 x q) = t. Find the total number of points (t) when a team answers six questions (q) correctly.
Mathematics
2 answers:
ch4aika [34]3 years ago
6 0
<span>If six questions are answered correctly, the team is awarded thirty points, because six times five is thirty. When added to the seven points they started with, the team's total score is thirty seven.</span>
Margaret [11]3 years ago
5 0
The given equation is:
t = 7 + 5q
where:
t is the total number of points
q is the questions answered correctly

We are given that the total of correct answers is 6 and we want to find the total number of points. Therefore, all we have to do is substitute with the number of answers in the given equation to get the total points as follows:
t = 7 + 5q
t = 7 + 5(6)
t = 7 + 30
t = 37 points
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4 0
2 years ago
Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩
NISA [10]

Answer:

\theta = 108.29

Step-by-step explanation:

Given

u =

v =

Required:

Calculate the angle between u and v

The angle \theta is calculated as thus:

cos\theta = \frac{u.v}{|u|.|v|}

For a vector

A =

A = a * b

cos\theta = \frac{u.v}{|u|.|v|} becomes

cos\theta = \frac{.}{|u|.|v|}

cos\theta = \frac{2*6+4*-7}{|u|.|v|}

cos\theta = \frac{12-28}{|u|.|v|}

cos\theta = \frac{-16}{|u|.|v|}

For a vector

A =

|A| = \sqrt{a^2 + b^2}

So;

|u| = \sqrt{2^2 + 6^2}

|u| = \sqrt{4 + 36}

|u| = \sqrt{40}

|v| = \sqrt{4^2+(-7)^2}

|v| = \sqrt{16+49}

|v| = \sqrt{65}

So:

cos\theta = \frac{-16}{|u|.|v|}

cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}

cos\theta = \frac{-16}{\sqrt{2600}}

cos\theta = \frac{-16}{\sqrt{100*26}}

cos\theta = \frac{-16}{10\sqrt{26}}

cos\theta = \frac{-8}{5\sqrt{26}}

Take arccos of both sides

\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})

\theta = cos^{-1}(\frac{-8}{5 * 5.0990})

\theta = cos^{-1}(\frac{-8}{25.495})

\theta = cos^{-1}(-0.31378701706)

\theta = 108.288386087

<em></em>\theta = 108.29<em> (approximated)</em>

4 0
2 years ago
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