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serious [3.7K]
3 years ago
5

Solve for 7 and 8 please

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0
To divide exponents they have to have the same base and then you just subtract the bottom exponent from the top exponent.

7) k × 3^9
----------- =
3^5

k × 3^9-5 =
k × 3^4 =
k × 81 = 81k

8) x^4 × y^10 × 2^11
------------------------ =
y^8 × 2^7

x^4 × y^10-8 × 2^11-7 =
x^4 × y^2 × 2^4 =
x^4 × y^2 × 16=
16x^4y^2
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a student found the volume of a rectangular pyramid with a base area of 92 square meters and a height of 54 Meters to be 4968 cu
Naya [18.7K]
It is not correct. 

The student found the volume by multiplying the base area with the height. He forgot to divide it by 3.

Formula to find the volume of the pyramid = 1/3 base area x height

volume = 1/3 x 92 x 54 = 1656 square meters 
6 0
3 years ago
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Help Me For Number 5 Through 8
lakkis [162]
#7 is kind of hard to read
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3 years ago
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let a = (a1, a2) and b = (b1, b2) and c = (c1,c2) be three non zero vectors. if a1b2 - a2b1 is not equal to 0. then show three a
Ksenya-84 [330]

Consider the contrapositive of the statement you want to prove.

The contrapositive of the logical statement

<em>p</em> ⇒ <em>q</em>

is

¬<em>q</em> ⇒ ¬<em>p</em>

In this case, the contrapositive claims that

"If there are no scalars <em>α</em> and <em>β</em> such that <em>c</em> = <em>α</em><em>a</em> + <em>β</em><em>b</em>, then <em>a₁b₂</em> - <em>a₂b₁</em> = 0."

The first equation is captured by a system of linear equations,

\begin{cases}c_1 = \alpha a_1 + \beta b_1\\ c_2 = \alpha a_2 + \beta b_2\end{cases}

or in matrix form,

\begin{pmatrix}c_1\\c_2\end{pmatrix} = \begin{pmatrix}a_1&b_1\\a_2&b_2\end{pmatrix}\begin{pmatrix}\alpha\\\beta\end{pmatrix}

If this system has no solution, then the coefficient matrix on the right side must be singular and its determinant would be

\begin{vmatrix}a_1&b_1\\a_2&b_2\end{vmatrix} = a_1b_2-a_2b_1 = 0

and this is what we wanted to prove. QED

3 0
3 years ago
Use the point-slope form linear equation given.
Agata [3.3K]

y-3=3(x+1)

opening the bracket

y-3=3x+3

y=3x+3+3

equation of the line in the form y=mx+c;

y=3x+6

therefore gradient=3

parallel lines have same gradient therefore gradient of the other line is 3

y--3/x-0=3

y+3=3(x-0)

y+3=3x-0

y=3x-3.

8 0
3 years ago
16 is a factor of 24.<br> O A. True<br> O B. False
Alexxx [7]
The answer is b/false I hope this help
5 0
3 years ago
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