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timama [110]
4 years ago
9

at a factory that produces pistons for cars, machine 1 produced 700 satisfactory pistons and 300 unsatisfactory pistons today. m

achine 2 produced 707 satisfactory pistons and 303 unsatisfactory pistons today. suppose that one piston from machine 1 and one piston from machine 2 are chosen at random from today's batch. what is the probability that the piston chosen from machine 1 is unsatisfactory and the piston chosen from machine 2 is satisfactory?
Mathematics
1 answer:
viva [34]4 years ago
5 0
<span>the proccess of choosing is independent so probability of choosing from machin1 is:300/1000 =0.3
choosing from machin2 is:707/1010=0.7
the total result is 0.3*0.7=0.21 ;</span>
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Ymorist [56]

Answer:

Một cm3 của khối kim loại đó cân nặng số gam là:

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Một khối kim loại cùng chất có thể tích là 4,5cm3 cân nặng số gam là:

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Step-by-step explanation:

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3 years ago
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ki77a [65]

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Answer:

Quarters: 18.909

Nickels: 49.818

Dimes: 37.818

Somewhere around those numbers.

Step-by-step explanation:

$11.00 total in coins

Nickel = $0.05

Dime = $0.10

Quarter = $0.25

(n*0.05) + (d*0.10) + (q*0.25)

Solve the equation for q.

q=\frac{1}{2} d

(n*0.05) + (d*0.10) +( \frac{1}{2} d *0.25)

Simplify the expression.

9d + 2n = 440

d - n = -12

Multiply both sides of the equation by -9.

-9d + 9n = 108

9d + 2n = 440

Sum the equations vertically to eliminate at least one variable.

11n = 548

n=\frac{548}{11}

Substitute the given value of n into the equation d - n = -12

d-\frac{548}{11} =-12

d=\frac{416}{11}

Substitute the given value of n into the equation q=\frac{1}{2} d

q=\frac{1}{2} *\frac{416}{11}

q=\frac{208}{11}

Finally

d=\frac{416}{11}        d = 37.818

n=\frac{548}{11}        n = 49.818

q=\frac{208}{11}        q = 18.909

6 0
3 years ago
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Answer:

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