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Anton [14]
3 years ago
13

Plz help me with this

Mathematics
2 answers:
likoan [24]3 years ago
7 0
Word Form: Two million nine hundred, forty seven

Expanded form: 2,000,000 + 900 + 40 + 7
Ber [7]3 years ago
4 0
I don't know what the expanded form is but the word form is two million nine hundred forty seven.
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Three judges measure the lap times of a runner and each measurement is different from the others by a few hundredths of a second
ohaa [14]

Answer:

Systematic error

Step-by-step explanation:

Assuming that none of the judges are biased, the most likely reason for this difference is the occurrence of systematic errors.

Systematic errors are errors introduced by inaccuracy in the experimental design, be it in the observation or measurement process.

In this case, the reaction time from observing the finish and stopping the clock for each judge might be different, which configures a systematic error.

6 0
3 years ago
If 3x – 9 = -2x + 16, then 7x=?
skad [1K]

Answer:

The answer to this problem is x equals 14

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find mL 1 and mL 2. ​
lesantik [10]

Answer:

8. ∠1=118° ∠2=118°

9. ∠1=72° ∠2=108°

10. ∠1=127° ∠2=127°

Step-by-step explanation:

8. In this problem, 118° is corresponding to ∠1, meaning they are congruent. ∠2 is supplementary with ∠1, meaning that together, they equal 180°. So, to get ∠2, you must subtract 118° from 180°

9. In this problem, 72° is same side interior with ∠1, meaning they are congruent. ∠2 is supplementary with ∠1, so you do 180°-72°=  108°

10. In this problem, ∠1 is vertical angles with 127°, making them equal to each other. ∠2 is corresponding with 127°, making them also equal.

5 0
2 years ago
Help! <br><br>3x10=(2x10)+(1x_)
motikmotik
3*10=(2*10)+(1*x) \\  \\ 30=20+x \\  \\ 10=x
8 0
3 years ago
If ∠WOZ and ∠WOX are supplementary angles and ∠WOX and ∠XOY are complementary angles, then what is the value of x and m∠XOY?
omeli [17]

Answer:

D.x = 6; m∠XOY = 18°

Step-by-step explanation:

Supplementary angles add to 180 and complementary angles add to 90

∠WOZ + ∠WOX = 180

108 + ∠WOX = 180

∠WOX + ∠XOY = 90

∠WOX + 3x = 90

∠WOX  = 90 -3x

Replace WOX in the first equation

108 + ∠WOX = 180

108 + 90 -3x = 180

Combine like terms

198 -3x = 180

Subtract 198 from each side

-3x = 180-198

-3x = -18

Divide by -3

-3x/-3 = -18/-3

x = 6

∠XOY  = 3x = 3*6 = 18

5 0
3 years ago
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