The first given equation is:
4x + 3y = 6
which can be rewritten as:
2(2x) + 3y = 6 .............> equation I
The second given equation is:
2x + 2y = 5
which can be rewritten as:
2x = 5 - 2y ........> equation II
Substitute with equation II in equation I to get the value of y as follows:
2(5-2y) + 3y = 6
10 - 4y + 3y = 6
-y = 6-10 = -4
y = 4
Substitute with the y in equation II to get x as follows:
2x = 5 - 2y
2x = 5 - 2(4)
2x = 5 - 8 = -3
x = -3/2
From the above calculations:
x = -3/2
y = 4
Answer:
p=4
Step-by-step explanation:
11x4= 44
44+10 = 54
Answer:
The domain and the range of the function are, respectively:
![Dom\{f\} = [0\,m,5\,m]](https://tex.z-dn.net/?f=Dom%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%2C5%5C%2Cm%5D)
![Ran\{f\} = [0\,m^{2}, 10\,m^{2}]](https://tex.z-dn.net/?f=Ran%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%5E%7B2%7D%2C%2010%5C%2Cm%5E%7B2%7D%5D)
Step-by-step explanation:
Jina represented a function by a graphic approach, where the length, measured in meters, is the domain of the function, whereas the area, measured in square meters, is its range.
![Dom\{f\} = [0\,m,5\,m]](https://tex.z-dn.net/?f=Dom%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%2C5%5C%2Cm%5D)
![Ran\{f\} = [0\,m^{2}, 10\,m^{2}]](https://tex.z-dn.net/?f=Ran%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%5E%7B2%7D%2C%2010%5C%2Cm%5E%7B2%7D%5D)
This answer would be acute because it equals under 45
The value of 2 in 204.75 is ten-thousand times the value of two in 103.52