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Mnenie [13.5K]
3 years ago
9

Stefani is purchasing a house and finances $410,350 of the purchasing price. The mortgage is a 30 year 7/3 ARM at 6.5% with a 4/

13 cap structure. What will the remaining balance be after the first seven years? (show work)
A= $371,023.06
B= $217,870.06
C= $357,112.36
D= $192,479.94

Mathematics
1 answer:
poizon [28]3 years ago
6 0
I used an online mortgage calculator.

Inputted the following information:
Loan amount: 410,350
loan rate: 6.5%
loan term: 30 years

It gave me the following results:
monthly payment: 2,593.69
annual payment: 31,124.29

31,124.29 * 7 years = 217,870.03 total payment after 7 years.

Based on the Yearly Amortization Table, the remaining balance after the first seven years is <span>$373,327.70

The figure is nearest to Choice A. 371, 023.06</span>

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alukav5142 [94]
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3 years ago
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Boating: A paddleboat moves at a rate of 12 mph in still water. If the rover’s current moves at a rate of 3 mph, how long will i
Lostsunrise [7]

The time taken by the boat to travel 32 miles downstream is 2.1 hours and for upstream 3.56 hours.

<h3>What is speed?</h3>

Speed is defined as the ratio of the time distance traveled by the body to the time taken by the body to cover the distance.

Given that:-

  • A paddleboat moves at a rate of 12 mph in still water. If the rover’s current moves at a rate of 3 mph.
  • how long will it take the boat to travel 36 miles downstream and 36 miles upstream?

The time taken by the boat upstream will be calculated as:-

( B + W ) Td = D

( 12 + 3 ) Td = 32

( 15 ) Td = 32

Td = 32 / 15 = 2.1 hours

The time taken by the boat downstream will be calculated as:-

( B - W ) Tu = D

( 12 - 3 ) Tu = 32

9 Tu = 32

Tu = 32 / 9 = 3.56 hours.

Therefore the time taken by the boat to travel 32 miles downstream is 2.1 hours and for upstream 3.56 hours.

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4 0
2 years ago
What are the values of x in the equation 4x^2+4x-3=0
ludmilkaskok [199]
I have an answer and an explanation!

ANSWER:X=\frac{1}{2}   (or) x= \frac{-3}{2}


Explanation:

<span>{Let's solve your equation step-by-step.}
</span>4 x^{2} +4x-3=0

<span>{Step 1: Factor left side of equation.}
</span>(2x-1)(2x+3)=0

{<span>Step 2: Set factors equal to 0.}
</span>2x-1=0 (or) 2x+3=0<span>
</span>
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3 years ago
ANSWER ASAP WILL GIVE BRAINLIEST! 30 POINTS!!
podryga [215]

Answer:

y=|x-1|-1

Step-by-step explanation:

hope that helps :)

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3 years ago
If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.
nydimaria [60]

Answer:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

Step-by-step explanation:

Given

\cos(\theta) = -\frac{2}{3}

\theta \to Quadrant III

Required

Determine \tan(\theta) \cdot \cot(\theta) + \csc(\theta)

We have:

\cos(\theta) = -\frac{2}{3}

We know that:

\sin^2(\theta) + \cos^2(\theta) = 1

This gives:

\sin^2(\theta) + (-\frac{2}{3})^2 = 1

\sin^2(\theta) + (\frac{4}{9}) = 1

Collect like terms

\sin^2(\theta)  = 1 - \frac{4}{9}

Take LCM and solve

\sin^2(\theta)  = \frac{9 -4}{9}

\sin^2(\theta)  = \frac{5}{9}

Take the square roots of both sides

\sin(\theta)  = \±\frac{\sqrt 5}{3}

Sin is negative in quadrant III. So:

\sin(\theta)  = -\frac{\sqrt 5}{3}

Calculate \csc(\theta)

\csc(\theta) = \frac{1}{\sin(\theta)}

We have: \sin(\theta)  = -\frac{\sqrt 5}{3}

So:

\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}

\csc(\theta) = \frac{-3}{\sqrt 5}

Rationalize

\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}

\csc(\theta) = \frac{-3\sqrt 5}{5}

So, we have:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)

Substitute: \csc(\theta) = \frac{-3\sqrt 5}{5}

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}

Take LCM

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

6 0
3 years ago
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