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kifflom [539]
3 years ago
8

What number should be added to both sides of the equation to complete the square? X^2+12x

Mathematics
2 answers:
Zanzabum3 years ago
8 0

The number that should be added to both sides is 16 because its half of b, which is then squared. You then get (x+4)^2=20, which you then square root both sides and get x+4=+-20 and then subtract the 4 to get x=-4+-20



White raven [17]3 years ago
7 0

for ax^2+bx+c

if a=1, and c=(\frac{b}{2})^2, then it comlpetes the square


x^2+12x

a=1, b=12

since a=1, c=(\frac{b}{2})^2=(\frac{12}{2})^2=(6^2)=36

add 36 to both sides of the nonexistant equation to copmlete square

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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

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4 years ago
If a sample of pure sodium has a mass of 8.2 grams and sodium has an average atomic mass of 22.99 g/mol, how many sodium atoms a
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8.2 grams = 1 mol
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First multiply the value of 8.2 to 1. Then divide by the value of 22.99 to determine the number of moles of sodium present in the 8.2 gram sample.

Then use the following equation to solve for sodium atoms.

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4 years ago
If you have 66 data observations in a sample, how many classes (bins) does the sturges' rule recommend for you to construct a fr
Iteru [2.4K]

According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7

Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.

Given,

n = 66

We know that,

According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

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Here, n is equal to 66 and by substituting the value to the equation we get:

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1 year ago
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b

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6 0
4 years ago
Across which axis was point A reflected​
Snezhnost [94]

Answer:

When point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

Step-by-step explanation:

When we reflect a point A across the x-axis, the value of 'y' gets negated, but the value of 'x' remains unchanged.

In other words, when point P with coordinates (x, y) is reflected across the x-axis and mapped onto point P', the coordinates of P' will be (x, -y).

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Thus, when point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

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Hence, point A is reflected across the x-axis.

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