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dangina [55]
2 years ago
13

Please help thank you

Mathematics
1 answer:
lina2011 [118]2 years ago
4 0
1)
answer
A. PQR = PSQ = QSR

2)
answer
B. MNO = MOP = PNO
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0= 8-2x divided by 5
Stells [14]

Answer:

Step 1: Simplify both sides of the equation.

0= 8− \frac{2x}{5}

0 = 8 + \frac{-2}{5}x

0 = \frac{-2}{5}x+8

Step 2: Flip the equation.

\frac{-2}{5} x + 8=0

Step 3: Subtract 8 from both sides.

\frac{-2}{5} x+8-8=0-8

\frac{-2}{5} x=-8

Step 4: Multiply both sides by 5/(-2).

(\frac{5}{-2} ) *( \frac{-2}{5} x) = (\frac{5}{-2} )*(-8)

<h2>Therefor, the answer is x=20</h2><h2 />

* Hopefully this helps. Mark me the brainliest:)!!!

3 0
2 years ago
A candy company makes boxes of chocolates. Each box has 32 chocolates total. Of those 32 chocolates 14 of them have nuts. If the
Agata [3.3K]

Answer: 266

Step-by-step explanation: This is a ratio problem. If there are 14 chocolates with nuts out of every 32 chocolates, you can use this as a ratio and set it up as a proportion.

(1) 14 chocolates w/ nuts / 32 chocolates = n chocolates / 608 chocolates

(2) Solve for n: 8,512 = 32n; n = 266

7 0
3 years ago
A waffle recipe calls for 2 and1/4 cups of flour. If Chun wants to make1 1/2 times the recipe, how much flour does he need?
balandron [24]
2 1/4 x 1 1/2 = 3.375 cups of flour
5 0
3 years ago
Serena has $130 in her bank account . Her account is compounded quarterly for 2 years at a 9.4% interest rate . What is her tota
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\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$130\\&#10;r=rate\to 9.4\%\to \frac{9.4}{100}\to &0.094\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{quarterly, thus four}&#10;\end{array}\to &4\\&#10;t=years\to &2&#10;\end{cases}&#10;\\\\\\&#10;A=130\left(1+\frac{0.094}{4}\right)^{4\cdot 2}\implies A=130(1.0235)^8
7 0
3 years ago
Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ
mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant.  But maybe you don't know it isn't and it's a "trick" to throw you off.  Hmm...

Anyways, the half angle identity for tangent is

tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.  

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5.  That makes the missing side, by Pythagorean's Theorem, -3.  Filling in our formula:

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) } which simplifies a bit to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }  and a bit more to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }

Bring up the lower fraction and flip it to divide to get

tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1} which of course simplifies to

-3.  Choice A.

6 0
3 years ago
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