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4 years ago

If an object is said to be moving at 10m/s due north. The measurement 10 m/s would be best described as

Physics

2 answers:

Arlecino [84]4 years ago

6 0

The answer is velocity

dmitriy555 [2]4 years ago

5 0

Answer: Speed.

Explanation :

It is given that if an object is said to be moving at 10 m/s due north. In this case, the velocity of an object is given. It has both magnitude and direction as well.

Velocity is a vector quantity. 10 m/s is the magnitude of velocity and it is moving towards the north direction.

We know that the sped of an object is the total distance covered divided by the total time is taken. It is a scalar quantity.

So, 10 m/s shows the speed of an object.

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In A. C. motor capacitor is used

natita [175]

Answer:

d. to decrease D. C.

Explanation:

d. to decrease D. C.

4 0

3 years ago

A hot air balloon is flying above Grovenburg. To the left side of the balloon, the balloonist measure the angle of depression to

Savatey [412]

Find enclosed file with a drawing and the calculations of all angles and all distances.

These are the results that you will find in it:

Angle x = 90° - 22°15’

Angle y = 90° - 62°30'

Angle z = 22°15’ = 22.25°

Angle w = 62°30’ = 62.50°

tan(z) = H/a => a = H/tan(z)

tan(w) = H/b => b = H/tan(w)

a+b = 4 => H/tan(z) + H/tan(w) = 4 => H [1/tan(z) + 1/tan(x) ] = 4

H = 4 / {[1/tan(z) + 1/tan(x) ] } = 1.35 miles

a = 1.35 / tan(22.25°) = 3.30 miles

b = 4 – 3.30 = 0.7 miles

I hope it is very useful and you understand it. Let me know.

Download pdf

6 0

3 years ago

A huge cannon is assembled on an airless planet (ignore any effects due to the planet's rotation). The planet has a radius of 5.

Ganezh [65]

Answer:

The projectile's speed as it passes the satellite is 1497.8 m/s.

Explanation:

Given that,

Radius of planet $r=5.00\times10^{6}\ m$

Mass of planet $m=3.95\times10^{23}\ kg$

Speed = 2000 m/s

Height = 1000 km

We need to calculate the projectile's speed as it passes the satellite

Using conservation of energy

$E_{1}=E_{2}$

$\dfrac{1}{2}mv_{1}^2+\dfrac{GmM}{r_{1}}=\dfrac{1}{2}mv_{2}^2+\dfrac{GmM}{R+h}$

$\dfrac{v_{1}^2}{2}+\dfrac{GM}{r_{1}}=\dfrac{v_{2}^2}{2}+\dfrac{GM}{R+h}$

$-\dfrac{v_{2}^2}{2}=-(\dfrac{GM}{R}-\dfrac{GM}{R+h}-\dfrac{v_{1}^2}{2})$

$v_{2}^2=v_{1}^2+2GM(\dfrac{1}{R+h}-\dfrac{1}{R})$

$v_{2}=\sqrt{v_{1}^2+2GM(\dfrac{1}{R+h}-\dfrac{1}{R})}$

Put the value into the formula

$v_{2}=\sqrt{2000^2+2\times6.67\times10^{-11}\times3.95\times10^{23}(\dfrac{1}{5.00\times10^{6}+1000\times10^{3}}-\dfrac{1}{5.00\times10^{6}})}$

$v_{2}=1497.8\ m/s$

Hence, The projectile's speed as it passes the satellite is 1497.8 m/s.

4 0

4 years ago

Points A, B, and C lie along a line from left to right, respectively. Point B is at a lower electric potential than point A. Poi

djyliett [7]

Answer:

A) The particle will accelerate in the direction of point C.

Explanation:

As we know that

potential at points A, B,C and D as V_A, V_B, V_C, V_D and it is clear from the question that

V_A>V_B>V_C

And we know that flow is always from higher to lower potential (for positive charge due to positive potential energy).

So the charge will accelerate from B toward C.

Hence, the correct option is A.

6 0

3 years ago

Two resistors have resistances R1 and R2. When the resistors are connected in series to a 12.7-V battery, the current from the b

OLEGan [10]

Answer:

5.065 Ohm, 1.935 Ohm

Explanation:

when the resistors are connected in series.

Rs = R1 + R2

by using Ohm's law

V = I Rs

12.7 = 1.81 x Rs

So, R1 + R2 = 7 Ohm ...... (1)

When the resistors are connected in parallel.

Rp = R1 x R2 / (R1 + R2)

Using Ohm's law

V = I Rp

12.7 = 9.06 x Rp

R1 x R2 / (R1 + R2) = 1.4 ohm

Substitute the value of R1 + R2 from equation (1)

R1 x R2 = 1.4 x 7

R1 x R2 = 9.8

$R1 - R2 = \sqrt{(R1 + R2)^{2}-4R1\times R2}$

$R1 - R2 = \sqrt{(49-39.2)}$

R1 - R2 = 3.13 Ohm ......(2)

By solving equation (1) and equation (), we get

R1 = 5.065 Ohm

R2 = 1.935 Ohm

5 0

3 years ago