If an object is said to be moving at 10m/s due north. The measurement 10 m/s would be best described as

Physics

2 answers:

Arlecino [84]4 years ago

6 0

The answer is velocity

dmitriy555 [2]4 years ago

5 0

Answer: Speed.

Explanation :

It is given that if an object is said to be moving at 10 m/s due north. In this case, the velocity of an object is given. It has both magnitude and direction as well.

Velocity is a vector quantity. 10 m/s is the magnitude of velocity and it is moving towards the north direction.

We know that the sped of an object is the total distance covered divided by the total time is taken. It is a scalar quantity.

So, 10 m/s shows the speed of an object.

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A man and his dog are “walking” on flat Street. He is pulling on his stubborn dog with a force of 70 N Directed at a 30° angle f

Delvig [45]

Answer:

X component of force is 60.62 N.

Y component of force is 35 N.

Force of gravity on the dog is 245 N.

Magnitude of normal force is 210 N.

Explanation:

Given:

Force of pull is, $F=70\ N$

Mass of the dog is, $m=25\ kg$

Angle of inclination is, $\theta =30$ °

Acceleration due to gravity is, $g=9.8\ m/s^2$

The free body diagram of the dog is shown below.

The X and Y components of force of pull is given as:

$F_X=F\cos \theta=(70)\cos (30)=60.62\ N\\F_Y=F\sin \theta=(70)\sin(30)=35\ N$

Therefore, the X and Y components of the force are 60.62 N and 35 N respectively.

Force of gravity on the dog is the product of its mass and acceleration due to gravity. Thus,

$F_g=mg=25\times 9.8=245\ N$

Therefore, the force of gravity on the dog is 245 N.

Now, consider the motion in the vertical direction of the dog. As there is no motion in the vertical direction, the net force along the Y direction is 0. In other words, the total Upward force is equal to the total downward force.

From the free body diagram,

$N+F_Y=mg\\N=mg-F_Y\\N=245-35=210\ N$