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omeli [17]
3 years ago
12

In A. C. motor capacitor is used

Physics
1 answer:
natita [175]3 years ago
4 0

Answer:

d. to decrease D. C.

Explanation:

d. to decrease D. C.

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When an object is placed 30.0 cm in front of a concave mirror, a real image is formed 60.0 cm
Marrrta [24]

Answer:

1 / f = 1 / o + 1 / i = (i + o) / o * 1

f = o * i / (o + i) = 60 * 30 / (60 + 30) = 1800 / 90 = 20 cm

Both the object and image are in positive space for a mirror

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2 years ago
Science, who ever gets this will get a brainlest
anyanavicka [17]
The answer is A because there’s so much heat in the core and pressure because of all of the layers of the earth
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A U-tube with a cross-sectional area of 1.00 cm2 is open to the atmosphere at both ends. Water is poured into the tube until the
Doss [256]

Answer:

0.89 g/cm^3 = 890 kg/m^3

Explanation:

Cross sectional area of U-tube ( A ) = 1.00 cm^2

volume of oil ( V )  = 5.00 cm^3

change between top surface = 0.550 cm

height of oil = 5 cm  ( volume / area )

height of water = 5 - 0.550 = 4.45 cm

pressure at the oil-water junction = Pressure on the second side of the U-tube at same level

Po * g * Hoil = Pw * g * Hwater

Po * 5 = 1 * 4.45

∴ Density of oil ( Po ) = 4.45 / 5  g/cm^3 = 0.89 g/cm^3

8 0
3 years ago
What two elements are named after Dimitri Mendeleev?
bezimeni [28]
I'm pretty sure there is only one element named after Mendeleev: <span>Mendelevium.</span>
8 0
3 years ago
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A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0
otez555 [7]

The given question is incomplete. The complete question is as follows.

A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0.90 m/s each second. The push force has a horizontal component of 20 N and a vertical component of 25 N downward. Calculate the coefficient of kinetic friction between the box and the floor.

Explanation:

The given data is as follows.

    F_{1} = 20 N, F_{2} = 25 N, a = -0.9 m/s^{2}

             W = 83 N

         m = \frac{83}{9.81}

             = 8.46

Now, we will balance the forces along the y-component as follows.

       N = W + F_{2}

           = 83 + 25 = 108 N

Now, balancing the forces along the x component as follows.

       F_{1} - F_{r} = ma

        20 - F_{r} = 8.46 \times (-0.9)

             F_{r} = 7.614 N

Also, we know that relation between force and coefficient of friction is as follows.

             F_{r} = \mu \times N

          \mu = \frac{F_{r}}{N}

                    = \frac{7.614}{108}

                    = 0.0705

Thus, we can conclude that the coefficient of kinetic friction between the box and the floor is 0.0705.

7 0
3 years ago
Read 2 more answers
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