Question

The scatterplot below shows the relationship between the number of gallons of gasoline in the tanks of 14 cars, and the maximum number of miles the cars can be driven on the given amount of gasoline.
Based on the data collected, which combination of gallons in the gas tank and maximum number of miles seems most likely to be possible?
A.0 gallons in the gas tank and 20 miles
B.9 gallons in the gas tank and 280 miles
C.11 gallons in the gas tank and 360 miles
D.19 gallons in the gas tank and 520 miles

Answer 1

B.9 gallons in the gas tank and 280 miles

Answer 2

Answer:

Option: B is the correct answer.

           B.9 gallons in the gas tank and 280 miles.  

Step-by-step explanation:

From the given figure we see that the line of best fit passes through the point (13,400) and (17,520)

We know that the equation of a line passing through two point (a,b) and (c,d) is calculated by using the formula

$y-b=\dfrac{d-b}{c-a}\times (x-a)$

Here we have:

(a,b)=(13,400) and (c,d)=(17,520)

Hence, the equation of line of best fit is:

$y-400=\dfrac{520-400}{17-13}\times (x-13)\\\\\\y-400=\dfrac{120}{4}\times (x-13)\\\\\\y-400=30\times (x-13)\\\\y-400=30x-390\\\\\\y=30x-390+400\\\\\\y=30x+10$

Now we will check each of the given options:

A)

0 gallons in the gas tank and 20 miles

when x=0 we have:

y=10≠20

Hence, option: A is incorrect.

B)

9 gallons in the gas tank and 280 miles .

when x=9 we have:

y=30×9+10

y=280

             Hence, option: B is correct.

C)

11 gallons in the gas tank and 360 miles

when x=11; we have:

y=30×11+10

y=340≠360

Hence, option: C is incorrect.

D)

19 gallons in the gas tank and 520 miles

when x=19; we have:

y=30×19+10

y=580≠520

Hence, option: D is incorrect.