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3 years ago

What is the volume of the rectangular prism

Mathematics

2 answers:

-Dominant- [34]3 years ago

8 0

Answer:

Step-by-step explanation:

V125BC [204]3 years ago

3 0

Answer:

Step-by-step explanation:

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A widget inspector inspects 12 widgets and finds that exactly 3 are defective.Unfortunately, the widgets then get all mixed up a

WITCHER [35]

Answer:

0.7455

Step-by-step explanation:

First, we note that there are C $C_{12|3}$ = 220 ways of selecting the defective items.

The probability that the inspector will have to test at least 9 widgets would be 1 minus the probability that the inspector will have to test 8 or less widgets.

This is 1 - P(8 or less widgets have to be checked)

1 - $\frac{C_{8|3} }{C_{12|3} }$

= 1 - 56/220

= 1 - 0.2545

= 0.7455

8 0

2 years ago

Read 2 more answers

Don’t understand this question will give brainless thing

____ [38]

The answer is 6.33 units.

4 0

2 years ago

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How do you write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1,1)

harkovskaia [24]

First you have to put it into point-slope form before you can write it in slope-intercept form which is y-y1=m(x-x1)

Y-1=2(x-1)
Distribute the 2 to the x and -1
Y-1=2x-2
Move it all to one side
Y=2x-1

7 0

3 years ago

Read 2 more answers

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0

3 years ago

Need help with #1 #4 #7 plz giving 15 points

valentina_108 [34]

Answer:

Q1: p = - 33

Q2: d = - 99

Q3: t = - 13

Step-by-step explanation:

Q1: $$ \textbf{-} \frac{\textbf{p}}{\textbf{3}} \hspace{1mm} \textbf{-} \hspace{1mm} \textbf{8} \hspace{1mm} \textbf{=} \hspace{1mm} \textbf{3}$